<p>Equation was y = -2.75x -0.25 I'm sure. Then you plug in f(4) or something and you get something lol. Not sure about the f(4) part.</p>
<p>it waas f(1) = -2 and f(-1) = 3 or I mixed up x and y.</p>
<p>EDIT: </p>
<p>Why is this above your post o__O</p>
<p>i got 1500pi.</p>
<p>hipster-I got n greater than or equal to 9! somebody said the answer was n greater than or equal to 6! but I don't remember that as an answer choice</p>
<p>"What was the f(1)=-2 question? I remember doing it.. it was in the middle of the right hand side page.</p>
<p>(1,-2) and what was the other point? What did we have to find.. like f(something else) right?"</p>
<p>We had to find the f(4), and I think the other point was like f(-1)= -3 or something</p>
<p>i agree with u IndiaRubber, it was 1500pi</p>
<p>@BigWeight: I thought the triangle/cone volume thing was 1500pi, but some say it was 2000pi.</p>
<p>^ Yes, I got the same thing, hipster (see above). For the XY rotation.. the triangle...was like 25, 20 or something?</p>
<p>The height of the cone was 20, the hypotenuse is 25</p>
<p>Use pythagorem to find the radius is 15 </p>
<p>Then 1/3 pi r^2 h</p>
<p>1/3 pi 225 20 = 1500 pi</p>
<p>EDIT: o_o I remember solving it that way but I don't remember putting down 1500 pi. I remember putting down 2000 pi lol</p>
<p>IndiaRubber:</p>
<p>The triangle was XYZ and had XY=20, XZ=15, and... doesnt matter what the hypoteneuse since it's the slant anyway. It was to be rotated ABOUT XZ, so the HEIGHT of the cone will be XZ=h=15. The RADIUS will be XY=r=20. (1/3)(pi)(r^2)h. This gives you 2000pi.</p>
<p>@hipster23: I think I got something like -11.25 or something for the f(4) problem.</p>
<p>Huh? For me the radius was already given as 20, and the height of the cone was 15.</p>
<p>So I got - 1/3(400pi)(15) = 2000.</p>
<p>^ Was the slant 25 or 15?</p>
<p>man lolilaughed^^^^ i thought i got every single one of them right. but nope, I can now see it was 113 not 112.5....the thing is, I dont remember 113 being an answer. OH WELL!</p>
<p>i skipped 4 though</p>
<p>and WANT IVY, nope the triangle was rotated about the XY</p>
<p>@Pynne - me too. yay!</p>
<p>i thought it was rotated about XY. hmm.</p>
<p>Yup it was -11.25. I am so sure it was 2000pi, since I actually got 1500pi at first and then re-read the problem and caught my mistake. If you got 1500pi then you rotated about the wrong axis. It was sort of misleading at first read, and so you're prone to do that. It was 2000pi though :</p>
<p>What about the weird one with the sum of the two zeros</p>
<p>The answer was like 10 right? the zeros were something along the lines of 7.3 and 2.6</p>
<p>^ Okay, well I don't even remember what I put for the answer. I just know how to do the question lol.</p>
<p>Me too. I got 2000pi, hope it's right.</p>
<p>^ Are you talking about question #49?<br>
Sum of two numbers = 10, their product is 20. What is the sum of their recipricals? The answer was A, 1/2. But yes, those were the 0s.. or around there anyway, I think.</p>
<p>no lolilaughed....it was .5 it was the reciprocal, not the actual numbers</p>
<p>I believe it was 20 for the height, 15 for the base, and 25 for the hypotenuse.
I remember checking it to see if it was a right triangle.</p>