November 2009 SAT II Physics

<p>it had 5 graphs and the questions had something to do of force vs. distance. I got the same answer for both but one was a inverse squared, F=kqq/rsquared and one was two charged plates (capacitor), so it was a regular inverse realtionship, F=A/D. Only one graph made sense for both so i put the same answer twice. </p>

<p>Was the answer to the place northwest or northeast?</p>

<p>I definitely put an inverse graph for one. Can’t remember the other…
For the planes flying, I put northwest. I was quite sure of it, because it makes sense just by looking at it, but people seem pretty split again.</p>

<p>Just to clarify the planes question - it was asking what the direction of plane Y (the one moving vertically) was from the perspective of plane X (moving horizontally right). If it’s moving to the right, then how can plane Y appear to be moving northeast (i.e. partly to the right)?</p>

<p>to come to think of it, northwest makes sense and i remember putting that after wasting like 1.5 min on that question</p>

<p>i don’t even remember the question, haha
damn</p>

<p>yeah i think northwest is right, does anyone remember the question that asked to find the vertical and horizontal components of a force acting at 60 degrees? tan was in a couple of the answer choices</p>

<p>i thought it only dealt with sine and cosine. so perpendicular comp is sine and parallel is cosine</p>

<p>yeah i put that one also</p>

<p>i just put the answers dealing with sin and cos
that was probably one of the easier questions
unless i didnt catch the trick or something</p>

<p>Actually I think it was the other way round - Horizontal was sine and vertical was cosine because the angle 60 degrees was like this:</p>

<p>.
60

…&lt;/p>

<p>Lol me and my diagrams. Perhaps I’m mixing up this question with a practice paper one, though…</p>

<p>i do remember a question with a diagram like the one you drew sci-fry
and im also wondering whether this was on a practice test or on the real thing today :stuck_out_tongue:
regardless, if it was that, then the force down the ramp is mgsin
but i remember the one on the test being pretty simple.</p>

<p>i think it was two men pulling a block through a defined path on frictionless ice? or was that not on todays test?:S</p>

<p>hey Sci-Fry can u do another one of your diagrams to show the lay out of the charges, towards the beginning of the test, not the one that looked like this…
+q -q
-q +q, but the other one</p>

<p>Hmmm not sure which one you’re talking about. I remember this one:</p>

<p>+q… -q…+q</p>

<p>This one asked which charge would have a resultant force to the left. The answer is the charge +q on the right side. That’s because it’s attracted to the -q charge with a greater force than it is repelled by the +q charge, so its resultant force is to the left.</p>

<p>The other one was:</p>

<p>+2q -2q
+2q -2q
This was the one with the greatest field/force at the centre.</p>

<p>alright thanks Sci-Fry</p>

<p>what was the one with the grams per cubic crap
that one was probably an easy one, but i had no idea how to do it</p>

<p>the current and watts one was 3600 right?</p>

<p>and the one with the $ sign, i completely forgot wat it was… does someone remember?</p>

<p>and the photographer with the tree and stuff, was that 0.0025 or something like that?</p>

<p>^Yeah, that’s what I got…haha i had 0.25 and then I went back and caught my mistake and felt super proud.</p>

<p>God, I was freaking out, but I feel a little better; I got most of the same answers as you guys. The bird was definitely higher above…we went over a scenario like that 10000 times in my physics class last year, so that was like the most redeeming moment of the test for me.</p>

<p>I think I got 0.025. The absolute magnification was si/so which was 0.1/100=0.001.</p>

<p>We know that abs(m) * ho = hi = 0.001 * 25 = 0.025m</p>

<p>Did a quick sparknote review the night before and saw these formulae. We don’t do this kind of optics in IB.</p>

<p>BTW, for the questions about the lenses/mirrors in the box, did you get the three arrows crossing as they come out the right side for the first one, and three diverging rays coming out the bottom for the second one? (sorry for the poor explanation).</p>

<p>Anyway, I’m out for now - I’ll just wait until results come out to see how I did… Nothing we can do now…</p>

<p>yes, that makes sense since concave lens is diverging and convex is is converge.</p>

<p>yeah
for the double one i put plane mirror and diverging lens (since the rays diverged)</p>

<p>anyone else? hahaha</p>