<p>25-minute sections are always experimental as far as I know.</p>
<p>yeah, i just realized it myself. ohh well, cant go undefeated, you know. but i did get the dog and all the other tricky questions right 
lol</p>
<p>Was the dog 12? I think it was like 3 2 2 1 = 12. Or was it 3 2 + 2 1 = 8? I forgot the question.</p>
<p>No it should have been 8, since the dog could not pass through the same door again. Thus it had 6 choices on the way to the owner, but only 2 coming back.</p>
<p>Yes, it was 12. For questions of that type I usually draw a possibility tree. At the top of the tree the first choice of doors, then each possible choice as a branch of the first. ;)</p>
<p>That’s what I was thinking mifune, but it asked for total choices, so I wasn’t sure whether you should add the two choices or multiply them.</p>
<p>Something like this:</p>
<p>[Monty</a> Hall problem - Wikipedia, the free encyclopedia](<a href=“http://en.wikipedia.org/wiki/Monty_Hall_problem]Monty”>Monty Hall problem - Wikipedia)</p>
<p>P.S. You can see them use the tree as solution too ;)</p>
<p>There was a question about two parallel lines asking for an angle</p>
<p>was it 100, 120, or 130.</p>
<p>Damn it ! Now I am hoping I got an 800 on at least a section 
Looks like math is out of consideration. Next up is writing ! :D</p>
<p>But the dog could not pass through the same door twice. That eliminates four possibilities on the way back. If it asked for the total choices (no restrictions), then it would have been one of the very first problems since that simplifies things to a large extent, not second-to-last in the section.</p>
<p>@CrosstheUniverse: I believe that the answer to that was 130 if you are referring to a problem #3.</p>
<p>Who cares where the problem is in the section. Show us how you get 8. Step by step. :)</p>
<p>There are 3 2 = 6 possibilities to get to the owner. There are 3-1 2-1 = 2 1 = 2 ways of getting back. I think you have to multiply 6 2 = 12 in order to get the total ways to get there and then back if you know what I mean.
Basically you can get there in 6 different ways and then come back through one of the two remaining doors. Then you can get there in the same 6 different ways and then come back through the last remaining door.</p>
<p>I am beginning to think that 12 may be right for the dog since it was supposed to be a multiplication instead of an addition. That was my rational originally during the test, but I switched to the addition. If so, thats probably a -2 for me. I was only considering the dog’s possibilities for one of the doors on the owner’s side that it entered.</p>
<p>Can’t believe I just missed a number 3. -1 for me.</p>
<p>@ YCM
the answer to the population one was choice A.
20,000> x > 30,000</p>
<p>or something</p>
<p>What was the answer to the question that had the variables on the number line where you had to choose whether I, II, and III were true?</p>
<p>II and III. dont really remmeber.</p>
<p>@mifune
I drew out every path on the dog one to make sure 12 was right lol. Say the dog room doors were 1A and 2A and the human’s were 1B 2B 3B
Basically you can:
go out through door 1A-next chose 1B 2B or 3B-(go back depending on which you chose), 2 different doors/ways. so if you went in 1B, go out 2B or 3B.(2 ways) in through 2B out–>1B 3B(2 more). in through 3B, out through 1B or 2B(2 more).
can only go back in to dog’s room one way, opposite door from which you went out= 2A</p>
<p>repeat same pattern starting in 2A
2A–>1B, back–>2B 3B
2A–2B—>1B 3B
2A–>3B—>1B 2B
can only go in through 1A for all of these. 6 starting from 1A+ 6 starting from 2A =12</p>
<p>easy, right? =)</p>
<p>What about the double digits one from 100-200 inclusive? 31?</p>