<p>That’s what I thought at first.
When I graphed the x^3 equation in my calculator, I found that the it was in fact -x^3.
Therefore, a<0.</p>
<p>what about the question asking about the inverse being equal to the y
it gave 3 options
1/x
1/x + 1
1/(x-1) +1</p>
<p>was it all 3?</p>
<p>I’m 90 percent sure a>0. anyone else?</p>
<p>I got the first and third</p>
<p>^^Yes I’m positive the function started out with ax^3. I didn’t spend a minute staring at it for nothing.</p>
<p>
Um. That doesn’t make sense?</p>
<p>i got the inverse one to be I and III only</p>
<p>why not the second one?</p>
<p>Yes. First & Third.
That question was somewhat time consuming because you had to switch x and y and solve for y. Took me about 1 minute to do 1 measly problem.</p>
<p>@Ihatetesttaking-For the inverse question, it’s first and third only.</p>
<p>After solving, you see that the second one doesnt have the inverse to be the same as the original function.</p>
<p>or plug it into the graphing calc… that thing saved my butt</p>
<p>Oh sorry perfectpixie.
I meant that when I graphed x^3 to see if it was the same curve as the one they depicted, I saw that it wasn’t x^3.</p>
<p>ok thank you,
and for the question asking if it fit the formula did u guys get
-3.7>x>1.1?</p>
<p>TheMathNerd- the end behavior of x^3 should have matched the graph. + infinity in the + x direction, - infinity in the - x direction</p>
<p>I believe there was a third piece to that?</p>
<p>ihatetesttaking- no, i got one of the answers with two parts… <em><x<</em>_ and x>__</p>
<p>I got a>0 for sure. because the end behaviour as x approaches positive infinity is going upwards, which means a is positive. and b=c, but c does not = d. that’s the whole answer (choice D i think).</p>
<p>for the Mo question, was it choice E- Mo/2^t?</p>
<p>and for the question which told you 3 points, and ask for where the roots are, was it (A) one real root between -2 and -1? </p>
<p>thanks!
did everyone think the test was hard or easy overall?</p>
<p>-3.7>x>-1.1 and x>1.0?</p>
<p>Wait, what did the graph look like?
They gave a picture of a graph.
I think I messed up then. I don’t even remember what I put.</p>
<p>I agree with the Mo and the roots^</p>