<p>50 was like 2.98 right?</p>
<p>Yeah, I think so too. A few more of trig, logs, and conics would have been helpful.</p>
<p>i also thought it was easy…1 blank and 1-2 errors? but i always misread and mess myself up that way</p>
<p>what was the one w/the t and 3x</p>
<p>it was the logic one</p>
<p>i didnt think i left any blank but now that i think about it i dont think i ever got back to that one</p>
<p>The answer to number fifty or the question with the cone is officially 4.76.</p>
<p>how so? 10charasardasd</p>
<p>**** i think i got that one wrong, forgot to re double the radius</p>
<p>@bacdjk: I think I got like 2 or something for the perpendicular question.</p>
<p>50 was 4.8</p>
<p>The one with t and 3x was t >= 3x</p>
<p>The question says t < 3x then 0 < y < 4. It says if y = 5 then what is t in relation to 3x. The above is the answer because if t is greater OR equal to 3x, then y can equal 5.</p>
<p>actually nvm, i think i might have gotten that one right</p>
<p>but on 50 didnt it ask for the shorter 1/2?</p>
<p>I think I got the slope to be 2, hopefully that’s what you’re thinking of. The question did ask to solve for y and not just the slope right :|</p>
<p>@RedCatharsis
I don’t get that question at all. Could you elaborate?</p>
<p>■■■.</p>
<p>6 blank and 4 wrong tops. Any hope for a 750+?</p>
<p>how is 50 done? the one about the cone.</p>
<p>If t<3x, then 0 < y < 4.</p>
<p>Given y = 5, which must be true.</p>
<p>That was essentially the question. Because 5 does not fall between 0 and 4, the first part of the statement must be false. For it to be false, t must be equal or greater than 3x.</p>
<p>
If that’s exactly what you got, yea, it’s around 750.</p>
<p>The cone was a radius of 3 with height of 6. The volume is then (1/3)pi(3^2)(6) = 18pi.</p>
<p>To cut the cone into two pieces of equal volume, they must each be 9pi.</p>
<p>V = 9pi
V = (1/3)pi(r^2)(h)
V = (1/3)pi(h/2)^2(h)
9pi= (1/3)pi(h/2)^2(h)
h = 4.76
~ 4.8</p>
<p>I felt it was comparatively hard to some of the practice tests I’ve taken…But then again, I haven’t really studied pre-calc material for months now and I’m in a calculus mindset and all at school, so that probably contributed to my less than stellar performance (though I still believe I pulled off an 800).</p>
<p>Solution to 50</p>
<p>find the volume of the original cone=56.48
half of that=28.27</p>
<p>the new little cone’s equation:
h<em>r^2</em>pi/3=28.27
h*r^2=27</p>
<p>Using similarity of the new and original cones the above equation is transformed to:
((3<em>x)^2)</em>6*x=27
x^3=0.5
x=0.793</p>
<p>The height of the small cone:
6*0.793=4.762</p>
<p>wait, what was the question again to number 50? wasn’t it like something cut a cone into two equal volumes? i forget.</p>
<p>yes. cut a cone into two equal volumes.</p>