<p>the scatter plot threw me off! how can a zero-aged tree have a 20 (cm?) diameter? That question is bogus.</p>
<p>protagonist i believe the answer was 3,hopefully lol</p>
<p>2 questions:
- Was the answer to the surface area question C?
- The question with the triangular prism was 400, right because it said the area of the trianuglar prism was the “area” of the base * the height. So since it was an equalateral triangle with side ten the area was 50. And 50*8=400</p>
<p>hey can anyone plz tell me the question of the diagonals in the hexagon (grid-in) and the answer plz</p>
<p>wHAT WAS THE ANSWER TO THE QUESTION ABOUT THE DISTANCE FROM POINT T TO LINE L.</p>
<p>Hexagon grid in was nine. </p>
<p>And for the equilateral triangle, the height if sqrt75 is I’m not mistaken, therefore the volume of the prism was 400sqrt3</p>
<p>The answer to the triangular prism problem was 200rt3. Let me explain. What they gave you was the sides of the triangle were 10 and the height of the prism was 8, so…
- To find the height, draw a line down from one vertice splitting the opposing base in half.
- Calculate the missing side (height) by using pythagorean’s theorem.
5^2 + x^2 = 10^2
10^2 - 5^2 = X^2
75 = X^2
X = 5rt3 - Use the 1/2<em>b</em>h formula to find the area of the base, and then multiply by height of prism.
1/2<em>10</em>5rt3 = 25rt3
25rt3*8 = 200rt3</p>
<p>Thus, the answer is 200rt3</p>
<p>it was y=4x…it couldn’t have been anything that had a +20 at the end because although it looked like 20 was the y-intercept there were a few under 20 in the middle of the graph, they were close to 0 … also if you graphed it on the calculator all the ones with +20 at the end were way too steep…the graph was gradually increasing</p>
<p>also:
(6,10)
2k-a
4 (for one of the fill-ins)
20 degrees (for the question with the 1/18)
62x^2
0 chocolates
x^-1/2</p>
<p>@miley07: Incorrect. Y = 5X + 20 was in fact the right answer. Because the line has to be suiting to ALL the point Y = 4X would simply not do that. This is why. On the graph at the point X = 25 the Y was EXACTLY 145. If you plugged in X = 25 to Y = 4X you are going to get Y = 100 and that is WAAAAY too small and would never suffice. Thus, the slope of Y = 4X is too small, and there, in fact, is a Y-intercept at Y = 20 thus, Y = 5X + 20</p>
<p>Actually I figured the answer to the number of positive integers under 1000 is 666 NOT 667. Why? because it’s asking for UNDER 1000, therefore 1000 itself isn’t included.</p>
<p>so 999/3 = 333
999 - 333 = 666</p>
<p>It was y = 5x + 20 because a line of perfect fit does not mean you have to hit all the points. You have to draw a line which will better represent the scatter of the points… The points obviously showed a y intercept closer to 20.</p>
<p>that’s incorrect it the answer was 1
let me explain: </p>
<p>(x+6)^2= x^2+12x+36
x can = -6 and the answer will be 0</p>
<p>another way to look at it is :
(-6-6)^2= 0 so the final answer is 1…I’m 99.99% sure</p>
<p>^I think that question is a bit obvious lol</p>
<p>tuftsbound,</p>
<p>you’re wrong. plug in -6 and tell me what you get.</p>
<p>i thought so too, but earlier someone said it was none for that question</p>
<p>OK TO PUT TO REST THE (X + 6)^2 = 0 PROBLEM LOOK AT IT THIS WAY. WE ALL LEARNED “PEMDAS” IN ELEMENTARY SCHOOL (Parentheses, Exponents, Multiply, etc.) AND THAT IS THE ORDER OF OPERATIONS. THUS, IF YOU PLUG IN -6 TO (X + 6)^2 YOU WOULD DO WHAT IS IN THE PARENTHESES FIRST (-6 + 6) WHICH EQUALS 0. THEN, WHEN YOU SQUARE ZERO, YOU STILL HAVE ZERO. YOU CAN ALSO DISTRIBUTE IF YOU WANT TO BE SURE BUT ORDER OF OPERATIONS WITHOUT DISTRIBUTING TELLS US IT’S RIGHT.</p>
<p>@gregrunt
that’s correct…it’s 1…for sure</p>
<p>Yeah 
It’s an obvious ■■■■■ question</p>
<p>Anyone help with this?</p>
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<p>I’m scared, I chose 4… But then 4 is based on the assumption that the lower angle is also 90 degrees.</p>
<p>@nyuismydream: There are an infinite number of possibilities so long as X > or = 4. Thus, 4 is a correct answer as well as 5, 6, 7, etc. But, if you look at this from a technical perspective, when they ask for the distance to a line, it is implied that it will be perpendicular to said line and the “shortest” distance. Thus, 4 was your SAFEST choice. But in my opinion it was a bad question and anything greater than 4 was fine.</p>
<p>Thanks, and yes, this was a terrible question… I hope collegeboard figures this out. Can we file complaints about the sat questions?</p>
<p>What about the question “if pr=pq and …=… (not sure if this is exactly right) and …=1, … 1what is …”? Isn’t the answer 1?</p>