<p>who remembers that stupid problem? the parabola and it’s mid-point line. The answer was a-2k but I spent like 3 minutes on it!</p>
<p>chair 2- you have to keep in mind the numbers 300, 600, and 900.</p>
<p>I put 757 for the one you guys are saying was 666 or 667…because I thought of it as 3 numbers divisible by 3 in every set of 0-9. Ex: From 0 to 9, 3, 6, and 9 are divisible by three. So I took that and multiplied it by 9 (0-99) and then 9 again (0-999). So I got 243, and subtracted this from 1000…but meh. Guess I got it wrong.</p>
<p>The numbers inside squares was just 97+99…</p>
<p>OHHHHH. now i remember numbers in squares. I got 99 + 97 which is 196.</p>
<p>You had to subtract it from 999, since 1000 was not included
referring to FreeFocus</p>
<p>What was the explicit problem for the squares one?
I don’t seem to remember that one.</p>
<p>^No, since both numbers in the squares were even you just had to divide them by two and then square them, and then subtract the two. it took me really long to figure out…</p>
<p>@Free…that doesn’t account for 30, 60, 90 (when there are 4 numbers divisible in a group of 10).</p>
<p>prime number thing was 36 right?</p>
<p>oh **** i didn’t see that it said all the odd numbers. i thought it just said all numbers.</p>
<p>huh? wait are we talking about the same squares? </p>
<p>the sum of the odd integers below the value.</p>
<p>“when k is squares of a number, and is divisible by 60, what is the least value of k?”</p>
<p>I put 3600</p>
<p>the question with r<s and y<s or somethign stupid was it just I or I and II?</p>
<p>deleted some stuff</p>
<p>Some one get remainder = 2?</p>
<p>^ Yes, remainder was 2.</p>
<p>“the question with r<s and y<s”</p>
<p>I put “only I” and I’m pretty sure its correct.</p>
<p>just I for the r<s and y<s i think.</p>
<p>remainder 2.</p>
<p>can anyone else confirm on 10x + 20??</p>
<p>^ Yes, it was only I.</p>
<p>^surface area.
was the answer 120 for the color (background, design) question that used combinations?</p>