<p>135th number was 8.</p>
<p>Anyone else for the Keisha question?</p>
<p>i also remember five</p>
<p>The 135th number was the 3rd one right? whatever that third one was</p>
<p>What does everyone think the curve will be?</p>
<p>Some of the harder ones I remember…</p>
<p>tan-1(25/3
common ratio 2/3
90 for highest median value
log(x^2 -2x) (something with an x^2 in it)
increasing from b to something and something to positive infinity (with the local mins and maxs)</p>
<p>yea it was the 3rd one i def remember that</p>
<p>I thought the graph was all real numbers because it asked about x not y.</p>
<p>the highest value was 80 not 90 i think and i confirm the common ratio, tan, and log answers</p>
<p>Was the watch one 21?</p>
<p>The highest median was 85… (80+90)/2
I got tan-1(3/25) for the tan one.
And I put an arithmetic difference of 90.</p>
<p>Im pretty sure the highest value was 90 because the median was in the third bar which had a range of 81-90, so 90 is the max of what it could of been. Anyone else confirm or disagree?</p>
<p>I disagree. The median was between the second bar (69-80) and the third bar (81-90). The highest median using two numbers from those sets is the median between 80 and 90, which is 85.</p>
<p>Haha, I don’t even know what you guys are talking about. I don’t take that as a good sign.</p>
<p>what did u gus put for the clock question</p>
<p>I put 21 degrees for the clock</p>
<ol>
<li>Is that what you got?</li>
</ol>
<p>This year was definitely harder than past years I thought.
I ended up having to guess for at least ten questions and usually I finish with time to spare and get a 32. </p>
<p>Considering canceling the score</p>
<p>It’s 21. How did you guys get a common ratio of 2/3? The question said it went from 270 to 180 and was linear, so isn’t that an arithmetic difference of 90?</p>
<p>And no, it was 90 for the median one. Did you guys actually do it all out? I wrote out all of the data (quickly) and the median was 90.</p>
<p>^Thanks Wanton 
makes me feel better now but hopefully I didnt misread anything.</p>