October 2010 - MATH I

<p>Well, CAN A -2 BE AN 800??? This test was kinda tough!</p>

<p>what about question 16? what is the domain of the function f(x) = 5(x-1)(x-2)/(x-1)(x-3) ? all real numbers except 3…or all real numbers except 1 & 3 ? I wrote except 1 and 3 … guess it’s wrong
and what about the question with the clay and the cube…edge = 8 inches and to find the thickness…something like that… ? I left it blank…
aahh…and question 48? f(x) and g(x) inverse functions…? what was the answer…?guess that was wrong too… :frowning:
hope the score would be greater than my previous 640…probably around 700… :frowning: pretty tough questions…some related to math II…not fair</p>

<p>First of all, its all reals besides 1 and 3, because the denominator can’t be 0. And the inverse one was, E - f(g(x))=x. Thickness i left blank also.</p>

<p>And 58 is right by the way. When you have a diameter, the triangle formed is a right triangle. Also, i think the curve will be much more generous than in the past. I felt like this test was much more difficult than the practices i took. I think -1 should definitely be an 800, and -2 probably 790. Does anyonee remember the answer to the asymptote question? I think it was x=4. I don’t completely remember the question though.</p>

<p>the asymptote question was x=4, and the denominator must be 0, so x^2 - c =0 , c constant, 16 - c = 0, and c = 16. Could u please tell me the complete answer to the inverse function question? How did u solve it?Thanks</p>

<p>It is simply a rule. Im learning it now in pre-calc. I guess i just got lucky. If you have two functions, f(x) and g(x), in order to test to see if they are inverses, you do f(g(x)) and g(f(x)), and if they both equal x, then they are inverses. Was the asymptote one choice (A)?</p>

<p>ok, thank u, I’ll remember the rule from now on. About the asymptote , i don’t remember exactly, but i guess 16 was choice D or C. and the question with the equator? Why were there answers with 10^9 or10^5? The 10s really confused me,cuz I thought the answer is smth with pi…</p>

<p>wait but they said that it was a diameter right? on the x^2 + y^2 one</p>

<p>pretty sure.</p>

<p>you guys knew how to solve the equator question?</p>

<p>yeeeeyyyy…720 :smiley: for me, this is great!! :X</p>

<p>most likely got a 800,but score is not out yet</p>