October 2011 SAT Mathematics

<p>x= 90% for the pollution eq</p>

<p>Was 0 the answer for the one with the graph of a parallelogram and you had to find the sum of the slopes? No numbers were given, i put 0</p>

<p>@nikanon I did that at first, and i had to reread the question which says that the cost was given in millions so you should have used 80 not 80million</p>

<p>Can someone tell me the exact question for the triangle with angle y,y,y? What value did they give you too?</p>

<p>One big triangle, split up into 3, with y degree angles at the top and 54 degree angles at the bottom two corners. you had to find x, you add up 54+54 = 108. 180-108 = 72 divided by 3 = 24 so y is 24. 24 + 54 = 78</p>

<p>@nikanon: To add onto joanybologna’s post of the cleanup, the equation was: 80=x-10/(101-x), which would lead to the answer of 90.</p>

<p>@joanybologna
@Seahawks506
@Kyrieah</p>

<p>thanks, I hate myself now <em>_</em></p>

<p>@joanybologna which angle was x?</p>

<p>Nevermind, thanks!</p>

<p>NOOOOOOOOOOOO I PUT 25 for the monument question. Could they not go in and come out the same path?</p>

<p>What was the answer to the question with f(x), g(x), and h(x)? I think it was a bit tricky because the question asked if f(x) + h(x) = g(x) or the chart was organized f(x), h(x), g(x) (not alphabetically). Can someone please confirm this answer?</p>

<p>it was supposed to be 0</p>

<p>ok Seahawks, that’s what I had…some other people on CC are saying other things…was this one experimental anyway?</p>

<p>did anybody remember the answer to the question that was a logical wording answer that was somewhat phrased like this
“if a number in the units digit is 0, then it is divisible by 5” then…
it was something along those lines</p>

<p>wait, isnt the formula for a paraboloa y= a(x-h) + k so the slope would be 5 not 2.5? because h (x-1) so h would be 1, so the initial point would be (1,0) and the other point (3,10)?</p>

<p>just because every seems to be asking about the two overlapping circle question…</p>

<p>it’s 96pi + 64</p>

<p>the radius of the circles was 8
so the area (if not overlapped) would have been 64pi each
but there were two so the total area is 128pi</p>

<p>but you have to subtract the overlapping section from 128pi</p>

<p>to find the area of the overlapping portion
you have to first figure out the area of the of the sector
which you find by multiplying the area of the total circle by 90/360 because 90 is the angle
you get 16pi for this
but you’re not done because you have to subtract the area of the triangle inside the sector which is (8 x 8) / 2 = 32</p>

<p>so from the total area of two full circles (128pi)
you subtract two of the chord area things (since there are two circles)</p>

<p>and your equation is:
128pi - 2(16pi - 32)
= 128pi - 32pi + 64
= 96pi +64</p>

<p>it’s really hard to explain in words…but i hope it was somewhat helpful!</p>

<p>I still don’t get the pollution one. Don’t you plug 80 into the function?</p>

<p>You plug 80 in as C(x) because C(x) is the cost. Then solve for x.</p>

<p>was the mondays question 9</p>

<p>Yes, it was.</p>