<p>I completely agree with MCS, but I think for the general population there will be a decent curve.</p>
<p>better than 1.2 you think?</p>
<p>Hmm… I thought that the multiple choice were really easy, and most FRQs. I did have a little with trouble with 5… Implicit differentiation to find second derivative?</p>
<p>I was kind of confused on that question where part b) asked for second derivative. Also, what did you guys get for another question that asked for over/underestimate? I had no idea how to do it so I just put over.</p>
<p>Multiple choice I think I did fairly well on, but the free response killed me. Much more difficult than I thought they were going to be.</p>
<p>Oh and what the heck was that MVT thing? Isn’t instantaneous velocity supposed to be equal to average velocity? WTH were they talking about? lol </p>
<p>A friend of mine just said inst. veloc. = av. velocity.</p>
<p>Instantaneous velocity is not average velocity.</p>
<p>Instantaneous velocity is the derivative of position as a function of time. Average velocity is just that, an average. If you travel 200 mile in 2 hours, your average velocity is 100 mph. But your instantaneous velocity may very well be different than that at any point on the trip.</p>
<p>I’m pretty sure that question did NOT follow the mean value theorem because there was a kink in the graph.</p>
<p>So that was TERRIBLE. My teacher never went over any questions involving position, velocity, acceleration. Oh my god -_-</p>
<p>Multiple Choice was a breeze–about 5-7 wrong…</p>
<p>Free response was tough. I think I got both the calculators one completely, if not all, correct. I think I got 6’s on both 3 and 4, and 2’s on 5 and 6…lol…</p>
<p>@ dmt
I know the difference, but instantaneous velocity equals average velocity (or was it average rate of change?) in mean value theorem. </p>
<p>However, the question seemed to argue against this. So how can f’(c) still be considered in the MVT? That’s the part that got me.</p>
<p>The idea with MVT is that f '(c) is going to be equal to the average rate of change of the function.</p>
<p>Tbomb: velocity, position, and acceleration problems are a huge part of ap calc… you should tell your teacher to make that a big part of the curriculum next year</p>
<p>It did not contradict the mean value theorem because the mean value theorem states that for avg vel to equal instantaneous velocity in the interval, the function has to be continuous as well as differentiable, this particular function was differentiable on one of the points on the interval because the graph was not smooth at that point</p>
<p>I meant to say not differentiable ^</p>
<p>My class decided this: The topics that the frq’s were over were pretty easy in their base form. Not really tricky subjects. However, the way the questions were formed (tricky equations, weird graphs, etc.) were something none of us had seen before, and we had covered a lot.</p>
<p>so you also mean’t did contradict?</p>
<p>oh oh I know what you mean, crap i think I may have worded my answer in a way that is not understandable… nooo!!!</p>
<p>F(x) has to be differentiable and continuous.Since F(x) isn’t differentiable in the interval, MVT wasn’t contradicted.</p>
<p>Bombed that baaadly. Graphing frqs were doable nd 3-6 were impossible. I think i go against the consensus for the mult choice in that i thought non calc was easy nd graphing hard. Looks like im not gettin the college credit :/</p>
<p>i thought the non calc mc was so much easier than the calc. weird. The frq’s were awful. bombed it.</p>