<p>Made a correction on the speed- redoing it shows that it’s .785 not .575. Also added alternate explanation on 5b. These should be the right answers, my calculus teacher, those teachers on the websites, and I got the same key.</p>
<p>1-
a) 1.017 degrees F/minute, the temperature of the water is changing at a rate of approximately 1.017 degrees per minute at time 12.
b) 16 degrees F- the water rose 16 degrees from 0 to 20 minutes
c) 60.79 degrees F, understated, the largest temperature is excluded in the left hand approximation and the temperature is strictly increasing over time.
d) 73.043 degrees F</p>
<p>2-
a) It’s going to the right because dx/dt is positive, slope= 3.055
b) 1.253
c) speed= .785, acceleration vector= <-.0411, .989>
d) .651</p>
<p>3-
a) -1/4, (pi-3)/2
b) 2, 1
c) at -1 and 1. -1 is a maximum because the sign chart shows it going from + to -, but 1 is nothing.
d) at -2, 0, 1. These are the points where f’ changes sign.</p>
<p>4-
a) 18.2
b) 19.6
c) 19
d) 19.8</p>
<p>5-
a) It gains weight faster at 40 because plugging in 40 to the rate given compared to 70 results in a greater rate.
b) db/dt= -1/25[100-B]. Using sign chart, 0= -, 200= +, so 100 is a point of inflection. The graph doesn’t show it. OR The graph must be concave down over the interval from 0-100, which doesn’t show in the graph.
c) y= 100-80e^(-1/5t)</p>
<p>6-
a) -1<=x<=1
b) 1/224 is the first neglected term and must be greater than the error according to ASRT. 1/224 is less than 1/200 so the approximation error is less than 1/200.
c) 1/3-3x^2/5+5x^4/7…[(-1)^n(2n+1)x^2n]/[2n+3]</p>