Does anyone’s school offer that AP Seminar class? I just discovered it on the collegeboard website, seems like a hassle of a class lol
@Frigidcold Why 12? I’ll be done with 11 by junior year, unintentionally lol.
@sjwon3789 I figure 15 (only taken 3 so far) is a nice number. Not too many so that I can still get 5s on all of them, but more than usual.
@sjwon3789 Also, any more and you start delving into ones that higher ranked colleges don’t give credit for.
@Frigidcold That’s true. When I was preregistering my APs (filling out my forms), I overheard some girl who got into MIT, deciding whether to go or not. And she was like, “I guess I won’t have to take APs if I go to MIT; yeah, MIT is really bad.”
Even Stanford gives credit to those who get 4’s.
Ok I think I’mma get off this site, because there truly is no point in stressing myself out by discussing the test especially since what’s done is done, and I suggest you all do the same and just be glad that the test is off your plate ^.^ If you really want to reduce your anxiety, just go to the ap score calculator and look at your composite score. If you get ~74 composite score and you are harsh with yourself, then you’ll be fine. Good luck to all of you taking other tests, and may all of you get satisfying scores when they come out in July! :]
@agupte Was the cone question answer A? I got A lol I forget what it was though… like .407 i think or something
Good point Dorfdude,all we can do is wait and hope for the best Good night CC.
Oh yeah, another thing – do they scan our work? I wrote it in pencil and I’m worried that they’ll miss some things.
Suddenly figured out the one part of the FRQ that I didn’t know how to do when I took the exam. What in the world can be more annoying than this.
Correct me if I’m wrong, but I think they get your actual booklet? Since you seal it…
I see that a lot of people got 1 for both m and b on the last part of the differential equation frq. I got m=2 and b=-2. Here’s my reasoning and I’m curious as to perhaps why this reasoning is flawed. The equation was dy/dx=2x-y. Since y=mx+b, dy/dx is also equal to m. Therefore, m = 2x-y. By manipulating the algebra, you get y = 2x-m. This is analogous to y=mx+b where m=2 and b=-m (so b becomes -2).
Also, if b=1 and m=1, then y=x+1, so dy/dx=1. If you set 1=2x-y, you can change it around to get y=2x-1, which contradicts y=x+1. You don’t get this contradiction when m=2 and b=-2.
Page 20 post 290… 15-2 with form O being more common and ofc I get form G
@laGrangeError You’re setting dy/dx equal to y=mx+b. You’re comparing those two; that’s wrong. m is your slope. You did that correctly but then you compared those two afterward. dy/dx is your m, not analogous to y=mx+b.
I don’t remember the whole exact question but you know your point. You’re given the point from part c. You plug that into your dy/dx to find your actual m value (not in terms of x or y). You use slope point formula, where y-y1=m(x-x1). You know what y1 and x1 is given that point, as mentioned earlier (part 3). You found your m value. You plug it all in. Your answer should be y=mx-m*x1+y1. So your m value is just the m value (next to the x) and your b value is -mx1+y1.
dy/dx is not analogous to y=mx+b. However, by setting m to equal 2x-y (which is dy/dx), you wind up getting y=2x-m. Take the derivative again: dy/dx=2. Also when x=0, you get the y intercept (-m). I’m pretty sure part c was unrelated to part d. The point (2,3) happens to be a point in one solution to dy/dx, but not on the linear solution.
Hold on… dy/dx=2x-y=m, then you took the derivative, which would make it into:
dy^2/d^2x=2-dy/dx=0, only under the assumption that m is a constant. m is not though; it’s 2x-y, remember? The deriative of 2x-y is 2-dy/dx, so it’s not equal to 0. The slope changes depending on x and y. This is not linear. The question is asking for a “tangent point” but m is not linear throughout the differential equation.
(2,3) is a point in the solution so you’re allowed to use it. I think you could’ve used any random point, actually.
hey guys!
for that question that said whats the graph is dy does not change or something like that…did u put the graph that was a straight line only?
also i forgot the put plus 30 for the water one …how many points do u think ill get off?
also i got concave up for the other one
and for the other one i set r(t)=d(t) but didnt get a chance to solve for t …
@chihuahua1 1. I and II, so no, not just the straight line.
2. 1 point
3. Yup, all concave up
4. Cool story
No
I thought the problem said that m and b were constants, but maybe you’re right. I guess we’ll find out if they release that frq.