<p>so who is freaking out about the calculus ap in two days? i am</p>
<p>i was wondering if anyone knew a program for Euler's Method...one where there is a link online that i can type into my calculator and not just download it cuz the downloads never seen to work, thanks guys!</p>
<p>Are you in AB or BC? AB doesn't cover Euler's Method. (The reason I ask is because for the first half of MY book, about 2/3 through the first HALF, there is a section on Euler's which my teacher has us skip.)</p>
<p>lol we did Euler's method in AB. don't remember it much so good thing I'm not expected to know it.</p>
<p>im in BC, there was a problem with Euler's method on a practice test i did for BC</p>
<p>I don't know if your teacher went over Euler's method similarly to how my teacher did, but basically, there are 4 key things to know when you're using Euler's method: dy/dx, x, y, and the equation of the line (y = mx + b)</p>
<p>Is this how your teacher explained Euler's method. I'm not sure if I'm being 100% clear, but in case I'm not, feel free to ask me to elaborate.</p>
<p>please elaborate</p>
<p>i totally do not get it at all</p>
<p>Euler's Method: </p>
<p>xn = xn-1 + h
yn = yn-1 + h(y'n-1)
Repeat for n = 1, 2, 3... </p>
<hr>
<p>Example:
h=0.2
Estimate y(1) if y'1=y-2 and y(0)=4
x0=0; y0=4; y0 = 4-2=2</p>
<p>x1=0.2
y1=4+0.2(2)=4.4
y'1=4.4-2=2.4</p>
<p>^Increase x0 by h to get x1. Multiply h by y'0 and add to y0 to get y1. Find y'1 by plugging y1 into the equation for y': Repeat step until you get to x=1. </p>
<p>x2=0.4
y2=4.4+0.2(2.4)=4.88
y'2=4.88-2=2.88</p>
<p>^Increase x1 by h to get x2. Multiply h by y'1 and add to y1 to get y2. Find y'2 by plugging y2 into the equation for y'1. </p>
<p>x3=0.6
y3=4.88+0.2(2.88)=5.456
y'3=5.456-2=3.456</p>
<p>^x3=x2+h. y3=y2+h(y'2). y3-2 </p>
<p>x4=0.8
y4= 5.456+0.2(3.456)=6.147
y'4=6.147-2=4.4147 </p>
<p>^x4=x3+h. y4=y3+h(y'3). y4-2 </p>
<p>x5=1.0
y5=6.147+0.2(4.147)=6.9766 </p>
<p>^x5=x4+h. y5=y4+h(y'4)</p>
<p>Excellent, Emmeline!</p>
<p>In case anyone wants to see an alternative but similar way to approach these problems:</p>
<p><a href="http://img462.imageshack.us/img462/3775/scan002001a8yy.jpg%5B/url%5D">http://img462.imageshack.us/img462/3775/scan002001a8yy.jpg</a></p>
<p>Good luck!</p>
<p>P.S.- Put cursor over the image and click the icon on the bottom left-hand corner to enlarge it.</p>
<p>AB!
I found myself so stupid becoz I'm gonna take BC next year...</p>