<p>i dont remember any. the last twenty were a blur, especially since i filled in random ovals for 5 of the last 6. i have a sinus infection and i turned every 4 seconds to cough into my sleeve haha.</p>
<p>what was the 400 pi quesrtion about</p>
<p>I think that was for the circle question and I got 20 pi.</p>
<p>um it was like the area of the inscribed circle … remember the coordinate one with (0,-20) and (0,20)</p>
<p>ACTUALLY …not even sure about this… can someone confirm the problem and the answer.</p>
<p>@SAT i actually laughed out loud when i saw the math at 12 haha.</p>
<p>and i know! im embarrassed! my math is probably at like -7 now…hopefully i stay in the 30s? I still think i have a 33 no matter what; R: 36 (with a curve, might’ve gotten one wrong but still not convinced), E: 36, S: 32, M:30. Even with reading as a 35 i maintain my 33 so fingers are crossed.</p>
<p>i forget the 400pi question but i remember getting it as an answer. and the 20pi answer was to the question about the arc length</p>
<p>I got 20 pi for the length of AB in the circle question.</p>
<p>I got 20 pi for the length of AB in the circle question.</p>
<p>Wait what… what was the exact problem? … was in the same problem that had the degrees… and the answer was 10?</p>
<p>@howmanyofme I got 100 pi for the area.</p>
<p>no 20pi was definitely the answer to the length of arcAB. the equation looked something like (180/360)2piR, with the radius being 20. so the answer was 20pi. (180 was the degree measure of the arc.)</p>
<p>i forgot the problem but i just used sector length thing:</p>
<p>s=(theta) X radius
s= 2pi X 10
s = 20pi</p>
<p>There was a large circle with a diameter of 40 and one inside of it with the bigger circle being its diameter making the smaller circle have a diameter of 20. The question asked what though? I remember putting 20 pi I think…</p>
<p>the area was 400pi, you have to do (degrees/360) multiplied by (pir^2). which was 400pi.</p>
<p>Yes I got 20pi also. That is correct…am sure. I got 10 for the (-20, 20) problem. For that k problem I got 18…I don’t see how it was -18 because you could do (x+1)(x+17) so K would be 18…right? Also…for the 90 deg problem…there were 4 interior angles right…so what I did was (4-2)180 to get 360, and then since that angle was 90 (the interior would be 270), so the answer I got was (360-270)=90?? I’m convinced I read the question wrong…</p>
<p>I got 100 pi for the area of the smaller circle as well</p>
<p>10^2 times pi = 100 pi</p>
<p>well that’s -1 ***</p>
<p>The two angles added up together were 45. At the time I just guessed because they looked like they added up to about that much but someone proved it earlier.</p>
<p>I didn’t think there was an area of 400? But it kind of rings a bell so maybe I said that. What was the question?</p>
<p>haha…it sure is…</p>
<p>@RR, it was -18. factor: (x-17)(x-1), when foiled = x^2 - 18x + 17 = 1. the question asked for what value of k would give two positive integers as answers.</p>
<p>I got 100 pi for area of small circle, 20 pi for arc length, 10 for x-coordinate, -18 for the k problem.</p>
<p>@efeens44: You are right</p>