<p>@Bugyloo
Yes that’s what I’m trying to say! :D</p>
<p>@LittleBrother001 the ans for that was 4…</p>
<p>Does anyone remember the remainder problem #7 on the grid in section it had something to with remainders and n+3 /7 I guess. I put in 1, what was the answer?</p>
<p>@Bugyloo no it was -4</p>
<p>Yes it was 1</p>
<p>Anyone else to confirm it was 1? </p>
<p>Also what was the answer for the quadrilateral with how many angles bla bla I already asked this but nobody answer me. I put 3 right angles is impossible</p>
<p>Yes I got it 3 also
I’m sure of this one
Cuz in any quadrilateral
The sum of all angles=360
So if 3 of these angles = 90
Then definitely the 4th should be also 90</p>
<p>3 is impossible cause if quadrilateral contains 3 right angles fourth also must be 90degreed…3x90=270…360-270=90</p>
<p>@knaar227 Yes I confirm it was 1 for the remainder question… Also I confirm it was positive 4 for the absolute value question… I asked many people about it, it is positive 4… it was absolute X-4… So to make that 0 you need 4.</p>
<p>could you write the question that of x-4…</p>
<p>Why would you want to make it 0, it asked for the maximum point which if you plug in -4 gives you the highest number. I’m confused!</p>
<p>^no t wasnt</p>
<p>The question was asking for the minimum value
Just plug-in numbers and see which one will give u the least value</p>
<p>100% they asked for minimum value… so if something is in absolute the smallest it can be is 0… Thus you will try to make the abs 0… The only way to make the abs 0 is by making X=4…</p>
<p>Buggyloo: yes it is 4.
There was a question with choices about x divisible by 2 or by 4 or by 8. Its answer choices were a) I only
B) I & II
And the other choices follow…
Can anyone remember it and its answer?</p>
<p>I got 4 too…</p>
<p>damn, I hate these stupid mistakes >:(. Also for the final post it was I, II, and III</p>
<p>I said divisible by 2 and 4…</p>
<p>yeah the divisble one… um… i got divisible by 2 and 4… not sure tho…</p>
<p>the parabola one is (5,0)… right?!</p>
<p>yes (5,0)…</p>