<p>For the one where it was Absolute value of (x-3)/(x-3), it was only greater than 3. Put in 3 and see what you get, you get a big 00000000 (actually undefined)</p>
<p>icyfire: no, its 39</p>
<p>i think the one with 2 polynomial is 3 or 4. Cause the equation would either be (x-a)(x-b) * (x-c)(x-d) for all different, but it said at least 1 pt different so the other possibility is (x-a)(x-b)* (x-a)(x-c). The 1st one has 4 zeros (distinct) while the 2nd has 3 distinct ones. Plz confirm this</p>
<p>werent only AB and BC needed??</p>
<p>i don't remember the question
but to solve the triangle, all you needed was the angle, ab, bc.</p>
<p>i got a^2 + 1 also jma</p>
<p>iostream, I don't think they gave us an angle.</p>
<p>thats what i put</p>
<p>what was question 1</p>
<p>you are solving for an unknown angle ABC, according to law of cosine, all three sides of the triangle are needed</p>
<p>to find the angle u need SSS, all of them (b^2=a^2 + c^2 -2accosB(beta)). so to find beta, you need b, a, c</p>
<p>No, because it wanted to find the value of the angle, not a side thrills.</p>
<p>And iostream, if u do 1=cosX^2 + sinX^2, and divide through by cosX^2 because secx^2 = (1/Cosx^2), u get that it equals 1 + Tanx^2.</p>
<p>wait i thot they gave us an angle</p>
<p>i guess ur right about hte bouncing one. however the sec one was definitely a^2 + 1</p>
<p>no, they didn't; they asked you to find the angle</p>
<p>wow, i feel like such a scrub.</p>
<p>i'm taking bc calc ap/linear alg. as a sophomore and i STILL make careless mistakes like that...</p>
<p>how many can you get wrong and still get 800?</p>
<p>wat was the last one (I think) where you were to find the radius of a sphere inscribed in a cube with edge s? Was is E (think it was s*(3)^(1/2))?</p>
<p>it was s(root 2) / 2 i think</p>
<p>and it was the radius of a sphere circumscribed around a cube, not inscribed inside.</p>
<p>for the radius of the sphere it should be s*root(3)/2</p>