<p>@Kiria</p>
<p>If I recall it correctly..
it asked for a equation, where f(x) and f(-x) give the same answers</p>
<p>x^5-3x^3+x=0 for sure
and 8/11 for sure</p>
<p>Was that choice A does anyone know?</p>
<p>b or c as far as i can recall</p>
<p>How can it be x^5 one when (-x) ^5 is -x^5? That cannot be it.</p>
<p>I looked for adding positive X ^ even exponent or - X ^ a negative exponent. I put either C or D, i think D.</p>
<p>Just plug in 2 for x^5 on, positive 2 = 28, (-2) = -28</p>
<p>Now that I think about it, i hope that question wasnt asking about like symmetry or some crap like that because all i remember is that they had to equal each other.</p>
<p>2100 or bust, just keep in mind that if all the coefficients become negative, you end up with</p>
<p>-(the original polynomial) = 0</p>
<p>which has the same roots.</p>
<p>2100 it is right. If you look at it another way, you can't have a constant in the polynomial. That is the only one that didn't (or 1 of 2, I forget).</p>
<p>to ppl who got 8/11</p>
<p>considering x is an infinite #,</p>
<p>how did you get 8/11?</p>
<p>is this the formula you used↓</p>
<p>(4/3-1)(4/3-7/8)</p>
<p>then how would it be diff for</p>
<p>7/8≤x≤4/3
7/8<x<4/3
or
7/8≤x<4/3
7/8<x≤4/3</p>
<p>could you tell me your solutions for each?</p>
<p>'cause I think your solution makes no diff between non-inclusive and</p>
<p>inclusive.</p>
<p>correct me.</p>
<p>
[quote]
yah dude you made the same mistake as I did; you used a permutation instead of a combination. Permutations only when order matters. Gah I wish I had been paying more attention when I took the test! I realized it after I was already on the Chem SAT II. Can anyone explain the x^5-3x^3+x problem to me tho? I'm not sure I get that, although it does work when I plug it into my calculator. Anyone mind solving it algebraically?
[/quote]
</p>
<p>Good thing I just learned this crap in calc. If all the exponents are odd, then the function is odd, odd being defined by f(-x) = -f(x). That was the question right?</p>
<p>Sanosuke: That is not what the question was asking. It was asking if f(x) = f( -x)</p>
<p>If i had the choices in front of me i could do the question easy, but while doing the test i was rushed and probably messed up but i remember that choices C and D stuck out at me.</p>
<p>to:pgcokie</p>
<p>The answers are the same.
since there're infinite real numbers in between, it doesn't make much difference to add 4/3 or 7/8.</p>
<p>Man! One more wrong.</p>
<p>I really hope the curve is 43, but it's probably 44 or higher. :(</p>
<p>Here's the other problem (at least how I see it) with the method that got 3/4 (or at least one person's method)...</p>
<p>You made them 21/24 and 32/24... Well, what if we make them 42/48 and 64/48? They're the same numbers, and if the 3/4 answer is correct, it shouldn't make a difference.</p>
<p>So, you have...</p>
<p>Below 1: 42, 43, 44, 45, 46, 47 (6 numbers)
Above or at 1: 48, 49, 50, 51, 52, 53, 54, 55, 56, 57, 58, 59, 60, 61, 62, 63, 64 (17 numbers)</p>
<p>17/(17+6)=17/23, which isn't 3/4.</p>
<p>3/4 = .75
17/23 = .739
...
8/11: = .727</p>
<p>I bet if I kept doing the same thing (making them 84/96 and 128/96 and so on), the fraction would keep getting smaller and smaller, and as the denominator approaches infinity, the chance would approach 8/11.</p>
<p>Thanx! I get it now.</p>
<p>I dont remeber the exact question, but i think it was number 2 or three. I remmeber the ansere choices were something like, a>0, a<0, b^2-2ac<0, b^2-2ac>0. For this one i put a>0. Does anyboy remember this question?</p>
<p>yeah i put a > 0 because it faces up... or something like that.
for the odd/even function one. you factor out the -1 from all the terms. if it doens't make sense, just thinkt hat you can divide both sides by -1 and come up with the original.</p>
<p>What was the question to the x^5-3x^3+x=0 answer? I have no clue what problem that is.</p>
<p>
[quote]
What was the question to the x^5-3x^3+x=0 answer? I have no clue what problem that is.
[/quote]
</p>
<p>They asked you to plug in f(-x) into all of the given choices and see which ones had the same solutions.</p>
<p>I can say with 100% confidence that the answer is B, the one with all the odd exponents. I plugged it into my graphing calculator and both the f(x) and f(-x) functions had the same zeroes, or solutions.</p>
<p>Does Barrons have a separate Math 2 book or do they only have a Math 2C prep book? I was looking for it in the store the other day and couldn't find the Math 2 book, so I just grabbed the Math 2C hoping it was the same thing..</p>
<p>I think I skipped this problem. So far, I i know I skipped 6, and I got one wrong. Im hoping that I don't get anymore wrong so I can get at least a 780.</p>