<p>For the f(100) problem, I noticed that when going from 0 to 10, the y value would go from 3 to 0. If you did the graph again, in 10 units, it would go up to 3 again. So it goes down, up, down, up, down, up, down, up, down, up. It ends on an "up", which is 3.</p>
<p>the one about the area of the triangle is 6 for sure.
.5<em>6</em>4*sin30=6</p>
<p>Call me a time-waster, but I went back and I actually wrote out the whole pattern till i got f(100), the pattern was smth like 31100113 (I can't remember), but anyway, that aside, I got 1. Which I am pretty sure is correct unless I made a careless mistake.</p>
<p>how can the triangle one be 6.46? if you make an altitude to the side with length 6, you'd have the hypotenus of 1 trangle as 4, use the ratio 30 to 60, you know the altitude is 2 and now you use 2x6/2=6 right???</p>
<p>I thought the 4-6 30 triangle problem was difficult as well. You can use the law of cosines, etc. to "solve" the triangle. I used a triangle solving program on my calculator to do this problem because I was short on time, and it wouldn't solve for area! Just for angles.</p>
<p>I couldn't remember Heron's formula (which is what they want you to use on this) and so with the measurements, I looked at the triangle by rotating my head to the left. Then everything clicked and it was a VERY simple problem -- one did not need a triangle solving program at all.</p>
<p>It looks like normal triangle I've solved in Physics before. When you have the measurements (4, 6, 30 deg) you can divide it into 2 seperate right triangles. The common edge on both of these triangles is the height of the triangle. Sin(30 deg.) * 4 = 2 (the height). The base is 6 (from the side). Base * Height * (1/2) = 6. The answer is 6.</p>
<p>Did anyone get #49???</p>
<p>Damn, I got 1 wrong so far (altitude of pyramid triangle - damn).</p>
<p>Did the probablilty one ask for numbers greater than 5 or at least 5?</p>
<p>I got 49.</p>
<p>The way those plots are setup is like"</p>
<p>2 | 6
3 | 4 5 5
4 | 5 5 8
5 | 2 3</p>
<p>That isn't the one from the exam because I don't remember it. I remember I got the answer though. They said "2 | 6 represents 26" at the bottom though and that is your key on how to read these if you did not know how before (like me).</p>
<p>Our list of numbers would be 26, 34, 35, 35, 45, 45, 48, 52, 53 and our median in this set would be 45. See how you read them? It was NOT the decimal answer, I know that, however I do not remember the answer.</p>
<p>How about this:
sum of numbers ranges from 2-20 (so 19 possibilities)
only 2,3,4,5 are not geater than 5</p>
<p>so 15/19=.789 or .8</p>
<p>i thought it was pretty easy. . .omitted about 4, don't think i got any wrong, but i probably did. . .hopefully high 700s</p>
<p>i got 6 for the area of that triangle as well. . .i love my law of sines and stuff.</p>
<p>silerace = genius. Damn, I see it now. Odd... The area was definitely 6 - no contest. So far only 1 wrong and 5 omit - looking decent (i usually always get a few wrong)</p>
<p>kent - im pretty sure the probability was .90</p>
<p>You set up a 10 by 10 grid and then add up the sums. The upperleft corner of the grid has 10 sums less than or equal to 5, and since there are 100 total sums (10X10 - though the sums repeat) you get 90 sums > 5/ 100 total sums = .90 probability</p>
<p>any idea on what the curve will be like? What raw score will get an 800 do you think?</p>
<p>Probably a normal curve. The consensus was that it wasn't super hard or super easy; just about right for a typical IIC test. So I'd say a raw of 43+ would get an 800.</p>
<p>fantastic. . .got the pyramid question one too. . .on the practice tests I was having trouble getting past 40 with respect to the time. . .performed well on the actual thing, heh.</p>
<p>w00t! I'm feeling much more confident about my performance than I did during the test. WOOHOO!</p>
<p>There are not 100 totals, that would be if 2+3 and 3+2 were different</p>
<p>That is true, but if you do the grid only 10 sums are less than or equal to 5 and the rest (90) are above 5. So its 90 sums above 5 and 100 total (regardless if they are the same or not) - so it's .90 probability that adding two numbers with replacement from 1 to 10 inclusive will result in a sum greater than 5.</p>
<p>Bugger. I either put .9 or .8 (I believe .8) for the probability one, simply because I did not know and eliminated every other choice because they aren't even close to realistic.</p>
<p>If i omitted 10 and guess at 2, will i have a chance at 750?</p>
<p>Does anyone remember their answer to the last problem:
abs(3+3)<5</p>