<p>err what i meant to say was that if your initial statement is true then when you compare its unequal (y=x comparison). you dont disprove x^2 = y^2 bc (2,2) works and 2=2</p>
<p>But for x^2 = y^2, x and y must not necessarily be equal for the equation to be true. For x^3 = y^3, x and y MUST be equal for the equation to be true.</p>
<p>i think i misunderstood the question. so its asking for if you hold that equation true then y must equal x right.</p>
<p>btw did you find the wording confusing on that one. it was the only question i spent an enternity on figuring out the meaning</p>
<p>That's the way I took it. Initially, I saw it the way you did but then it didn't make sense because it was asking for the one correct one, not the one incorrect one. Very bad question.</p>
<p>i was wondering about calling my friend college board up and seeing what they might do about it. i think it was a terribly written question and made everyone i spoke with confused.</p>
<p>comments?</p>
<p>i didn't think that was the question though for the ferris wheel, crap the way i remembered it was, "In one revolution, for how many seconds is the height below h, so i plotted the graph and looked at one period of the function, i found the two points where f(x)=30 and then found the diff. b/w those x values, did i misinterpret the question?</p>
<p>we are talkin about the y=x then which equation holds true</p>
<p>for y=x, x/y=y/x isnt right because x and y cant be 0.
the answer is x^3=y^3</p>
<p>lol i know my bad, i hadn't refreshed in a while, so i had a delayed response, so did anyone else put 10.25 for the ferris wheel one? see i foudn the first two spots where y =30 and then subtracted the x's to find the time interval, did i misinterpret what the ? was asking???</p>
<p>i put y^3=x^3 also, b/c if x were pos. y could be neg. and x squared would still equal y squared, so that one is right out, there was one where cross multiplication would just get u back to y squared equals x squared again, so that was out, and then i can't remember the other two, but they were wrong as well</p>
<p>thats what i did, but i dont remember what i got. how did you find the 2 points? i used a graph.</p>
<p>i graphed the equation and in y2 put the eq. y=30
then used the calc. to find the intersection points for me, then i subtracted those values to get an interval</p>
<p>also seven nights how did u solve the volume sphere one? i def. didn't get 5,000 something, i did 4/3pi r^3 for the bigger sphere then subtracted the one for the smaller sphere, got 4/3pi11^3 - 4/3pi (since one cubed is still one) and got 17511</p>
<p>and i don't know, i think the curve on this one should be a bit nicer than usual, i thought it was harder than the tests i practiced with....</p>
<p>the answer for the concentric spheres is D, because choice E was the volume of the bigger sphere, and D was 4 less than E. this made sense because the volume of the one with radius 1 was about 4.</p>
<p>sphere one was (4/3)pi<em>(11)^3 - (4/3)pi</em>(1)^3.... difference of volumes.</p>
<p>thus it's (5324/3)pi - (4/3)pi = 5571.09</p>
<p>(make sure you take out the volume of the small sphere, one of the answers was just the volume of the big sphere (5575.28) and since the radius of the small one is 1 theyre REALLY close)</p>
<p>i also put 10.25 or whatever the 10ish answer was for the ferris wheel. i did the same thing... graphed the eq and y=30 then subtracted from one pt to the other.... am i wrong?</p>
<p>for the castle one, i distinctly remember that the "peaks" were at 0, 7, 14, etc. f(2) was 1. take multiples of 7 until youre close to 100, so 7*14=98, so then f(100) has same value as f(2), which is 1. others i'm not sure about, but this one i will defend to the death. i am positive it is 1.</p>
<p>one more.... i don't remember the problem completely, but the one w/ the prime numbers.... kinda threw me off. all i remember is it was one of those (I), (II), and (III) problems. it said something about prime numbers greater than 2, and i picked 3 and 5. when the equations were all untrue, I was about to grid (A) "none", but then i tried 3 and 7. the first eq was a + b + 1, where a and b were the numbers, and this gave me 11 for a prime number. i dont remember the other 2 eqs, i just remember they didnt work w/ 3 and 5 or 3 and 7, but i didnt have time to try more. so i ended up putting just equation (I), which i believe was letter (B). anyone remember this one?</p>
<p>D was 17,511 right?</p>
<p>P.S.: Making claims about what the curve you expect the College Board will give is totally pointless. Every exam thread that I've ever read has had the people who messed up on the test claim how the curve should be better than usual. It's only the people who screwed up who say this because they hope it will help them. In actuality, the people who did well on the test (those actually used to these tests) seldom make generous predictions. I don't say this to be an ass; I only say this so that people don't give false hope to the people who are worried about their grade.</p>
<p>no wait i think i got 5571, lol where am i getting that 17,000 from i'll never know, that wasn't an answer choice was it? i fear i may have typed it into my calc wrong or something and the testmakers anticipated that, was 17,511 a choice?</p>
<p>D was 5571</p>