<p>studybuddy - you did it right but i think you messed up on the answer. (4/3)pi*11^3 is about 5275 or something like that. Subtract (4/3)pi and you get like 5270. Its definitely a 5000 number</p>
<p>someguy - i tried 3 and 5 as well and was going to put none but then i tried 5 and 7; 5+7+1 = 13 so "I" worked. So I put "I" only.</p>
<p>dude im still confused over the ferris problem, it appears i answered the question of "in one revolution how many seconds is the h<30" which i thought is what the ? asked...no? Also, if anyone knows how i typed it into my calc to get 17,000 for sphere lemme know, i wanna make sure i didn't also do that accidentally during the test</p>
<p>i thought that was the q for the ferris wheel. i did the same thing as you... i think it was 10.25.</p>
<p>i've been sittin here tryin to figure out how you coulda put that in to get 17,000something.... ive tried everything and i cant make it wrong... even with no parentheses it works. i think C was 5571 and D was 5575 or somethin like that</p>
<p>those equations for prime numbers have to hold true for all and if they work for just one data set then its obviously wrong.</p>
<p>plus the def of a prime number is a number divided by itself and one</p>
<p>when you multiple numbers you inherently get another factor whihc makes it not a prime number</p>
<p>was 17,000 an answer choice? for some reason i can remember putting both down, like i kinda remember having an answer of 17k and kinda remember having an answer of 5k....i don't know im thinking about cancelling i know i missed like 2-3 for sure and i skipped 2 and if i missed more than im anticipating.............ARG, I WANTED AN 800 on all my practice tests i got 800s....</p>
<p>The ferris wheel question asked for what value t (in seconds) would h(t) = 30.</p>
<p>h(t) = 29 + 25cos(pi/10(t-3))</p>
<p>so 30 = 29 + 25cos(pi/10(t-3))</p>
<p>1 = 25cos(pi/10(t-3))</p>
<p>Then just plug values into your calculator (if you have a graphing one it's so easy to put all the parenthesis in and such). I tried A, which was 7.87 seconds, and boom it worked.</p>
<p>Seven Nights - so that means only expression "I" COULD be true. r + s + 1 could be a prime. 5+7+1 = 13</p>
<p>starry calm down the avg for MAth 2c usually allow you to miss 6 points and then the 800 drops down incrementally down</p>
<p>and btw chill out. an 800 or 760 ISNOT going to make the diff whether you get into a or b college its the sum of all things</p>
<p>i prob. had a number on the calc. screen when i typed in 11^3 so it did 11^3 times something, so i almost for sure didn't do that during the test, it just worries me that i could make such a careless error now, when im not under pressure and stuff....just to humor me, can anyone definitively say whether or not an answer in the 17,000s was a choice?</p>
<p>The answer for the abs(x+3)<5 problem is the distance from -3 is less than 5.</p>
<p>seven nights thats why i ruled out equations 2 and 3. those were clearly multiples.</p>
<p>i was thinkin about that w/ if it doesnt work for one data set its all wrong.... but the word "could" was in the question.... not "must". </p>
<p>math IIC is turning into english.... when will it stop?</p>
<p>its not a test of your intelligence its a test of how well you can decipher what ETS wants from you</p>
<p>yeah seriously. i still dont know if i understood what the ferris wheel prob wanted from me</p>
<p>I'm 99% sure this is what the ferris wheel problem wanted:</p>
<p>The ferris wheel question asked for what value t (in seconds) would h(t) = 30.</p>
<p>h(t) = 29 + 25cos(pi/10(t-3))</p>
<p>so 30 = 29 + 25cos(pi/10(t-3))</p>
<p>1 = 25cos(pi/10(t-3))</p>
<p>Plug and chug (haha my old science teacher told me that). t = 7.87 seconds.</p>
<p>I explained the ferris wheel problem on page 1 or 2 of this thread, FYI.</p>
<p>i dont see how you get 1.00 sec there.... and i coulda sworn it said "how much time" did it spend under 30ft or somethin like that</p>
<p>crypto86: Your plug and chug is incorrect. 25*cos(pi/10(1-3)) = 20.22. 20.22 + 29 != 30.</p>
<p>somguyUIUC: Look on page 1 of this thread. I did the math for the entire thing.</p>
<p>slice, i think that we are just disagreeing on what the ? asked i never remember any "from the bottom" stuff, only "during the first revolution"</p>
<p>granted 7.87ish is a point at which the ferris wheel is 30ft off the ground.... but in your explanation on the first page you say the question is "how much time" did it spend below 30ft.... so you need to figure out where it comes back to 30ft again and then subtract, no? maybe i still dotn get it. i do see how 7.87 is a point where the wheel is at 30ft.... but there's more than one answer for arccos of a given quantity.</p>