<p>volume of cube was 8, not area</p>
<p>so if you if you found the diagonal of the base which is root 2, pythag that with the hieght of the cube, 2, and you get root 6</p>
<p>am i wrong?</p>
<p>I don't think it was because i had that problem and I believe that I had CR experimental.</p>
<p>wait volume was 8 so each side of the cube 2. since the sphere was inscribed in the cube. wouldnt that mean the each side of the cube would also be the diameter</p>
<p>The sphere... was the diameter 2?</p>
<p>Well for the cube one I did pythag theorem twice: I did it with both sides as 2 at the bottom of the cube (The diagonal) and then with the diagonal I did it again with a length at 2. Blah I probably got it wrong, I even forgot the answer!</p>
<p>elliot34, a correct method to do that problem was the third root of eight is two, so each side of the cube is two. Now, the question asks for the diagonal of the cube and you would have to find the diagonal of the bottom square to do this. That ended up being root eight [square root of the sum of two squared and two squared]. Root eight squared plus two squared is twelve and the square root of that is two root three.</p>
<p>diagonal of base was 2root2, not 2, pythagify that with 2 and you get root12, which is 2root3, the correct answer</p>
<p>nevermind i'm wrong, it's 2 root 3</p>
<p>what did you guys get for the one about the 6 points on a plane (also was it an experimental questioN??)</p>
<p>30 line possibilities, I think. I used the counting principle.</p>
<p>6 choices x 5 choices = 30 possible</p>
<p>for the writing about teddy roosevelt with the semi colon, was it </p>
<p>something like this)</p>
<p>not only an reformer; but he was also a something</p>
<p>or</p>
<p>not only a reformer, he was something</p>
<p>those choices may be completley wrong, anyone rmemeber?></p>
<p>it was 15 for that one.</p>
<p>atomicbomb22, i got 15. 6x5 wouldn't really work because there're three points that are on one line.</p>
<p>was it a grid in</p>
<p>i ended up going with A, "not only a reformer; but he was also..."
it seemed wrong but all the other ones seemed even more wrong</p>
<p>for 6 points ina plane, isn't it 21 because 6+5+4+3+2+1.</p>
<p>15 line possibilities. im positive; we just did one like that in calc just yesterday.
i got y^2 also for the inverse one. whatd you guys get for the graph of the function that was doubled?? i Put A.</p>
<p>sibsagar12 you mean the 6 points? no it was multiple choice</p>
<p>I'm pretty sure it was 15 possibilites - I made a hexagon</p>
<p>was the line one a grid in</p>