**Official** NOVEMBER 5 SAT I Thread!

Test Preparation
81

<p>yes, I had the scatterplot question. </p>

<p>Math question, #18 grid-in: Given a square with sides of 3, a smaller square with sides of sqrt 2 inside the larger square, and a common center for the two squares. If a circle were to be drawn inside the large square but outside the small square (touching neither), what is a possible value of the radius of the circle?</p>

<p>At first I thought that the radius could be anything greater than 1/2 the diagonal of the small square (which would be 1), and less than 1/2 the diagonal of the large square (which would be 1.5 x (sqrt 2). But then I thought that, no, the upper limit would actually be equal to 1/2 of the SIDE of the larger square (which would be 1.5). So I ended up answering 1.4</p>

<p>Anyone else remember this one? Did I get it wrong? Tricky problem.</p>

82

<p>no... so I guess that's the experimental one. I had math. What is the point of doing the experimental section, anyway?</p>

83

<p>2400SAT - that's right. I did the same thing. Hell, I even answered 1.4, too!</p>

<p>BTW that was NOT the experimental section.</p>

84

<p>so collegeboard knows how hard a question is for future tests-.-</p>

85

<p>i answered 1.45, because i got that half the diagonal of the inner square was 1.4, and half the side of the outer square was 1.5. i think you guys probably did it right, though, and we could answer anything between 1 and 1.5. did you guys anser "308" for that one asking for the product of P an R? i think it was 11 times 28. the math this time around seemed, overall, harder than the last 2 times i took the SAT I.</p>

86

<p>I don't know what questions you guys are talking about, but I did the SAT here in Australia and I didn't see any of those questions?</p>

87

<p>different test.</p>

88

<p>How is that possible? Shouldn't everyone be doing the same test so that scaling and what not can be done fairly?</p>

89

<p>internationals have diff tests b/c of time zone stuff.</p>

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<p>Math question, #18 grid-in: Given a square with sides of 3, a smaller square with sides of sqrt 2 inside the larger square, and a common center for the two squares. If a circle were to be drawn inside the large square but outside the small square (touching neither), what is a possible value of the radius of the circle?</p>

<p>I think,
1.1<x<1.4</p>

91

<p>it is between 1 and 1.5 exclusive.</p>

92

<p>i got a different test guys. Im from Vietnam</p>

93

<p>308 is the correct answer to the p and r grid-in question.</p>

94

<p>are you sure about the 1 and 1.5 inclusive? cuz i'd be ecstatic if it were...but wouldn't it touch the tip of the square (that is the diagonal?)</p>

<p>and what about the parabola translation question? was it f(x) - 3 or f(x - 3)</p>

95

<p>Ebonytear:</p>

<p>So you have an outer square with an area of 9 and an inner square with sides of length sqrt (2). The radius of the circle has to be larger than half of the diagonal of the square with sides of sqrt (2) and smaller than 3/2. Using the pythagorean theorem, half of the diagonal of the inner square is 1, so 1 < x < 1.5 exclusive.</p>

<p>F(x) - 3 for the parabola question</p>

96

<p>Here in canada we got a diff test too. its the one with african music thingy. </p>

<p>strange, the october sat's were same across the board</p>

97

<p>darn on both accounts.</p>

<p>why is it f(x) - 3 and not the other?</p>

98

<p>for f(x) - 3, i spent a bit of time on it, plugging in values... pretty much just plug in 0... f(0) = 2, and on the graph of g(x) the y intercept was -1, so the equation for g(x) was f(x) - 3, and so g(0) = 2 - 3 = -1</p>

99

<p>f(x - 3) shifts the graph to the right, not down.</p>

100

<p>wow, lol...that was sad...yeah, i get that now</p>