<p>So my language class is taking a lot of my time and I would just like to take it P/F - don't want to drop it -- but realize I could get a C if I have to spend more time on my required courses in CS and the final exam schedule could be conflicting.</p>
<p>If I change to P/F I will have less than 36 units taken for a grade-- does that mean I'm no longer considered full time and I mess up my financial aid or does a class taken P/F still count toward my status as a full time status?</p>
<p>I asked my RA-- didn't know.
I would rather not approach the CS freshman advisor...he was miffed enough when I didn't take freshman english this fall...we didn't get off to a good start.</p>
<p>Thanks--</p>
<p>Better get studying. Doesn’t get easier next semester.</p>
<p>Where did you hear that the policy was “36 units taken for a grade” for full time status? I decided not to take a class as pass/fail at the last second last year, but had filled out all the paperwork and consulted with my counselor. He never said a word about me dropping below full time status. CMU’s policy under the hub documents just says ‘36 units.’ </p>
<p>Also, to pass a P/F class, you only need a D :D</p>
<p>Furthermore-- a P/F class won’t be able to count as a prerequisite for anything else, and it won’t count towards your QPA. So if the class is Elementary German, you couldn’t take Intermediate German without re-taking Elementary for a letter grade.</p>
<p>I didn’t hear anything about the policy- -that was my question. HUB says 36 units— so I want to know if the 36 units means all units or only those taken for a grade – quality points reflected on the transcript?
I also have CCM and Freshman immigration for P/F.</p>
<p>Anyone know…</p>
<p>Language too time consuming-- but still fun-- I doubt I’ll continue to the next level…way too much time where I need that time on my other math and CS classes.</p>
<p>I know that seniors often take 3 classes and then a bunch of stucos to round out their units, so I doubt it’s 36 QPA-factorable units – more like 36 units in total.</p>