<p>A steel bar is 6.5M and weighs 325 N. It rests on two supports, 3.00 M apart, w/ equal amounts of the beam extending from each end. suki, who weights 575 N, stands on the beam in the center and then walks towards one end. How close to the end can she come before the beam begins to tip?</p>
<p>I have been stuck on this last problem of my homework for like an hour. Any ideas or anything... please help. thanks.</p>
<p>This is a simple torque problem. Set one of the support as the center of torque and find the torque clockwise and counterclockwise. You will find that at a certain point that force unequals. If you are still stuck, I'll post a solution later on this evening.</p>
<p>i did say torque c = torque cc.
then i set the torque L = torque R but I know this is wrong because i am missing 2.</p>
<p>I'm getting 1.6 meters. If anyone else can confirm that would be great.
(375N)(3.25m)=(575)(x+.5)
Solve for x and you get it. My logic is the weight is counter and the force of Suki times the distance that she moves plus the distance from one center of torque eqauals the maximum amount she can walk before the beam tips. I put one support on the left, the second 3 meters to left, and had her walk to the right. Sorry if I am wrong. Also you are accepting this help voluntarily, I take no responsibility if it is incorrect.</p>
<p>Opps sorry, wrong answer, she can walk 1.6 before the beam tips. Which would make it a total of 1.15 from the tip. Answer wrong question.</p>
<p>Gyros 321, can you confirm. Is my logic flawed?</p>
<p>my 375 and 575 were switched but thats probably my fault. What is the (x+.5). Anyhow its ok. I think my teacher grades on completion for homework. I dont know if its correct. I have not talked to my physics teacher yet.</p>
<p>the (x+.5) is the distance she walk plus the distance from the center of torque</p>