<p>I am a little confused on this problem and would appreciate a little help....</p>
<p>A ramp is 18 m long and 4.5 m high.</p>
<p>a. What force parallel to the ramp is required to slide a 25 kg box to the top of the ramp if friction is neglected?</p>
<p>b. What is the IMA of the ramp? Got this-4</p>
<p>c. What are the real MA and the efficiency of the ramp if a parallel force of 75 N is actualy required?</p>
<p>I will probably kick myself when I get the answers...</p>
<p>I don't what IMA and MA are, but the parallel force required is 61.3 Newtons.</p>
<p>parallel force = mg<em>sin(theta)
theta = arcsin(4.5/18) = 14.4775
parallel force = 25</em>9.81*sin(14.4775) = 61.3 N</p>
<p>Or you skip the whole arcsin to sin step, it's superfluous.</p>
<p>That's right. Damn. I should've gotten that.</p>
<p>BTW, IMA is ideal mechanical advantage and MA is actual mechanical advantage. IMA is equal to the effort displacement divided by the resistance displacement, and MA is equal to the resistance force divided by the effort force. Basically FrDr=FeDe, which in turn equates to Wo=Wi (work input and output).</p>