physics problem

<p>I have been trying this problem for a while now and i can't seem to get the right answer. i know that part a is somewhere between 4 s. and 5s. and i got 45.1 for the speed.</p>

<p>A stone is thrown vertically upward with a speed of 13.0 m/s from the edge of a cliff 78.0 m high (Fig. 2-32).</p>

<p>(a) How much later does it reach the bottom of the cliff?
s
(b) What is its speed just before hitting? </p>

<p>m</p>

<p>V^2-13^2=2<em>78</em>10
v=41.6
t=5.5</p>

<p>are you taking the maximum height?</p>

<p>Because the new distance is 95.2 m</p>

<p>you don't need to.
just consider total displacement</p>