A monatomic ideal gas at pressure P = 105 Pa is in a container of volume V = 10 m3 while at temperature T = 30ºC. How many molecules of gas are in the container?
(A) 447 (B) 2888 © 6.02 × 1023
(D) 2.39 × 1026 (E) 1.74 × 1027
Someone please explain this!
Thanks!
@APScholar18 Use the ideal gas law PV = nRT where
P = 105 Pa (do you mean 105 or 10^5??)
V = 10 m^3
R = 8.314 J/(mol*K)
T = 303.15 K
Then solve for n (in mol). Because it is monatomic, you can simply multiply by Avogadro’s number to get the number of molecules.
@MITer94 I mean 10^5 Pa.
@MITer94 Thank you! I believe I got it now. Answer should be D.
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