<p>was the answer for that chart with time and distance the average acceleration was 1.3m/s^2</p>
<p>yeah it was 1.3</p>
<p>jma.</p>
<p>the vertical velocity is positive when the ball is going up, and eventually will be zero at the top. then it will be negative on hte way down. therefore the answer was (D)</p>
<p>what about the question with the 3 different wire I1=I2=I3...was that right?</p>
<p>damn i think i got that one wrong.</p>
<p>thats what i put dan</p>
<p>there was a question about a pV diagram and the change in internal energy, does anyone know the answer?</p>
<p>what about that question with capatienct was it 20V or 20x10^-6 or something</p>
<p>AZN, that is what I said from the start. A graph that was initially positive and that went through the x axis and became negative with a constant negative slope throughout. </p>
<p>THe change in internal energy would be the same for both since they had the same starting and ending points.</p>
<p>I got 20x10^-6 since q= capacitance times voltage. </p>
<p>What did people get for the engine question where they gave you the temperatures. I just plugged that into (Th-Tc)/Th</p>
<p>the internal energy is the same.</p>
<p>okay sorry jma. misinterpreted. i thought you were saying a 0 slope.</p>
<p>anyways, how about the one with which two resistors would provide highest current? i put 1 & 3.</p>
<p>i put 1 and the 3...R directly prop 1/I</p>
<p>I put 1 and 4. I first put 1 and 3 but i then realized that if i used 4, there would be a parallel aspect which would reduce the total resistance and thus increase current.</p>
<p>thats what i put
for 3 and 4 did u put they equaled the same</p>
<p>For the graph of electromagnetic energy and frequency, did anyone put a straight line through the origin. At first I put the one that did not begin at the origin but no where did it mention photoelectric effect. As a result, I based on E=hf and changed my answer.</p>
<p>jma: i think that is correct.</p>
<p>really? i thought 1 and 3 would still be series</p>
<p>if it were 1 and 4 wouldnt 2 and 3 be the same?</p>
<p>Can someone add me to the chat. My aim account is smarba22</p>