physics subject test-ish

Test Preparation SAT Subject Test Preparation
1

<p>Can somebody help me with these questions pleasee?? it might even help you study for the SAT II test! thanks so much in advance!</p>

<ol>
<li><p>A bicycle has a tire with outside diameter of 24 inches. THe bicyclists pedals such that the bicycle accelerates from rest to 10 mph in 5.0 seconds. What is the angular acceleration of the tire?</p></li>
<li><p>Two capacitors with capacitances of 1.5 and 0.25 uF, respectively, are connected in parallel. The system is connected to a 50-V battery. What charge accumulates on the 1.5 uF capacitor?</p></li>
<li><p>IN a 2-dimensional Cartesian coordinate sy stem the x-component of a given vector is equal to that vector's magnitude multiplied by which trigonometric function, with respect to the angel between vector and x-axis?</p></li>
<li><p>What is the magnitude of the force needed to accelerate a 20 kg cart from rest to 0.50 m/s in 2.0 s?</p></li>
<li><p>The two ends of a 6.0 kg plank rest on scales. A 4.0 kg mass is placed one-quarter of the way in from one end. THe two scales register weigths of: </p></li>
<li><p>All batteries use what type of current to work?
Sinusoidal current, alternating current, direct curernt, invert pase current, or pulse currrent (choose one)</p></li>
<li><p>A player kicks a football at an angle of 30.0 degrees above the horizontal. THe football has an initial velocity of 20.0 m/s. FInd teh horizontal component of the velocity and the maximum height attained by the football.</p></li>
</ol>

2

<p>Sorry but can somebody please answer my questions please???</p>

<p>Also, if we take 2 subject tests in one sitting, can we cancel one score but not the other?
thanks.</p>

3

<ol>
<li><p>final angular vel = linear vel x radius = 10 mph x 24 inches (gee so many conversions to do, I don’t like this problem!)
Then you use angular acceleration = final angular vel x time
Sorry I really hate those conversions so I’m not going to deal with those numbers. Do you really think SAT will test you those??</p></li>
<li><p>effective capacitance = (1/1.5 + 1/0.25)^(-1) = 0.214 mF(when two capacitors are in series… you know.)
Then you have Q = 0.214 x 10^-6 x 50 = 1.06 x 10^-5 F.
note this q is the same for both capacitors since they’re in series.</p></li>
<li><p>v(x) = v cos(angle)</p></li>
<li><p>f = ma = 20 x 0.5/2 = 5Newtons</p></li>
</ol>

<p>5.are there two scales? then I guess it’s (3+1) kg and (3+3) kg. not sure.</p>

<ol>
<li><p>direct current</p></li>
<li><p>vx = v cos(30) = 20 x cos(30)=3.09 m/sec
max. height = vy^2 /(2g) where vy = 20 sin(30)= 10 m/s and g = 9.8 m/sec^2
So max. h = 100/19.6 which is about 5 meters</p></li>
</ol>