please post the WEIRDEST/HARDEST SAT I MATH QUE u have ever seen

<p>^ :( i wanted to solve....bt hey,good solution by diamond :)</p>

<p>i solved it differently which consumed more time (30 seconds)....with diamonds method it takes 10 to 15 sec....thanks to diamond</p>

<ol>
<li><p>The price per person to rent a limousine for a prom varies inversely as the number of passengers. If nine people rent the limousine, the cost is $70 each. How many people are renting the limousine when the cost per couple is $105?</p></li>
<li><p>8^r=4^t, the ratio of r to t is?</p></li>
</ol>

<p>These are not hard questions but it's easy to make a mistake if you rush through them.</p>

<p>another way to solve for fig's question -
each point is 360
(3x360)-180-180-180 = 540</p>

<p>180 from triangle and the 2 other 180 from supplementary angles</p>

<p>wow october,thanks for your method ....... its really intelligent of you :D</p>

<p>Thanks gluttony.</p>

<p>BTW answer to 1 and 2 are 12 and 2:3</p>

<p>I got another question -
3^27 what digit is in the one's place</p>

<p>october,i think the digit in the one's place is 7 ...... bt my method isn't good....some1 please submit a good method</p>

<p>my method:
3^27=(3^3)^9=27^9=(27^3)^3=19683^3=blah blah blah.......as we see that there is a 3 in the last place of 19683,so after multyplying it for 3 times whatever the number we get,that would end with 7 (the 7 of 27).....correct me if i am wrong and post a better method</p>

<p>bte:i shall solve the same way if i am asked to find out the one's place of 2^99</p>

<p>Can you explain your other two problems, october4th? I got 6 for the first one and 3/2 for the second one. :/</p>

<p>Edit: AH I SEE.</p>

<p>@ october4th</p>

<p>Is the answer 7?</p>

<p>3^1 = 3
3^2 = 9
3^3 = 27
3^4 = 81
3^5 = 243</p>

<p>Units digits alternate in a 3,9,7,1... pattern</p>

<p>So, at 3^27, we're done with 6 repetitions of 3,9,7,1. The pattern repeats itself again: 3, 9, 7 - that's the 27th one, if I'm not mistaken.</p>

<p>Although gluttony's method seems much better.</p>

<p>i can explain october's problem....
solve for 1. 7 people are asked to pay each 90 $.so they have to pay 630 $ in total.in second case,a couple has to 105 $,that means 52.5 $ per person.....so divide 630 by 52.5 and tadaaaaa,u will get 12 :D</p>

<p>solve for 2.its really easy.....
8^r=4^t
or, (2^3)^r=(2^2)^t
or,2^3r=2^2t
or,3r=2t
or,r/t=2/3.....answer :D</p>

<p>your right.
there's a pattern in the one's place.
3^1 = 3
3^2 = 9
3^3 = 27
3^4 = 81
3^5 = 243
3^6 = 729
3^7 = 2187
3^8 = 6561</p>

<p>3^27 = 3^(3+4+4+4+4+4+4)</p>

<p>for the other two questions -
1. you probably overlooked the word "per couple" so divide 105 by 2. </p>

<p>9x70 = n x 52.5
n=12</p>

<ol>
<li>8^r=4^t
2^3r = 2^2t
so you prabably got 3r=2t
r:t is also r/t</li>
</ol>

<p>r/t = 2/3</p>

<p>2/3 = 2:3</p>

<p>thanks DIAMOND,i hate these pattern problems.....every time i take a practice test,i beg god not to put me up for a pattern que :(</p>

<p>october & diamond,thanks for your solution for 3^27.......diamond's solution gave me an hasty idea about how to solve and now october's pattern breaking down & showing (3+4+4+4+4+4+4) corrected my stupid misconcept</p>

<p>Don't get fixated on scores bro, just do the best you can do and no one can take that away from you, otherwise you'll never win. Besides even if you achieve a perfect score, once you get into MIT or GT or Cal Tech your going to realize its about learning and expanding your knowledge not about grades. At least you should, good luck on your quest.</p>

<p>****, I wasn't here and you had a fun time with questions :D any more?</p>

<p>those asterisks didn't contain the f-word! :| lol</p>

<p>X_ _X
The figure above represents four offices that will be
assigned randomly to four employees, one employee
per office. If Karen and Tina are two of the four
employees, what is the probability that each will be
assigned an office indicated with an X ?
(A) 1/16</p>

<p>(B) 1/12</p>

<p>(C) 1/6</p>

<p>(D) 1/4</p>

<p>(E) 1/2</p>

<p>ouch,i got this wrong >.<</p>

<p>(2/4)* (1/3) = 2/12 = 1/6</p>

<p>lol can u explain lil more</p>

<p>first one of the two girls gets an office so 2 outta the four available offices are desired...so 2/4 ...then after that 3 offices are left out of which the remaining 1 X is desired so 1 outta 3.. and we want both of these occurrences to occur, so we multiply 2/4 and 1/3 .</p>

<p>ahhhhhhhh,you're right. what i did was 1/4 then x 1/3 T_T
i forgot that first choice has 2 slots.</p>