<p>hello </p>
<p>i was looking for help.
i have to do a few problems for my calc gt class, and im stuck:</p>
<p>find the derivative of</p>
<p>2/square root x</p>
<p>i dont want the answer necessarily, but i need help in the process bc i keep getting stuck</p>
<p>thanks so much</p>
<p>I would look at it like 2 times the x raised to the 1/2. </p>
<p>Then, and I dunno if you've learned it yet, but the 2 is a constant so just move it aside. Then take th 1/2 and bring it to the front as a coefficient of X, and lower the 1/2 power by 1 degree so it becomes -1/2 power. I dunno I guess I'll have to give the answer.</p>
<p>2* x^(-1/2) * 1/2</p>
<p>So those cancel and you get </p>
<p>1
_</p>
<p>x^(1/2)</p>
<p>thanks
im still a little confused</p>
<p>isnt it</p>
<p>f(x+h)-f(x)</p>
<hr>
<pre><code> h
</code></pre>
<p>Oh lord I forget all a/b that...after awhile they'll show you the shortcut like I used and that's basically what you'll use. Get ready...calculus classes do that for a long time. They make you use the drawn-out method for awhile and then say "now here's how normal ppl do it."</p>
<p>Sry it's been too long. I don't remember that method very well.</p>
<p>Yeah, in general, if f(x) = ax^q, then f'(x) = aqx^{q-1}</p>
<p>ahhhh</p>
<p>what is that</p>
<p>haha unless you have to show your work using that other method use the one il bandito said</p>
<p>f(x) = function
a = coefficient
q = exponential power
x = x</p>
<p>So in your problem</p>
<p>a = 2
q = 1/2
x = x</p>
<p>oh. yay for shortcuts
well that will help me get the right answer, and then ill work backwards. </p>
<p>thanks!</p>