<p>The average of the shaded regions was equal to the sum of the unshaded regions.
Since there was 2 shaded regions and 2 unshaded. Both unshaded was equal to one shaded region. Were solving for the unshaded.</p>
<p>2u=s
u + s = 180
u + (2u) = 180
3u = 180
u = 60</p>
<ol>
<li> 728 </li>
<li> 1 more point </li>
<li> 1.5</li>
<li> .5</li>
<li> 108 degrees</li>
<li> 60 degrees</li>
<li> 4=r</li>
<li> (150 + 10 x) / x</li>
<li> ¼</li>
<li>15</li>
<li>7156</li>
<li>310</li>
<li>x=2 y=3</li>
<li>I,II,II </li>
<li>the middle side is 3</li>
</ol>
<p>im not sure these r right but anyways,
does anyone remember the other 13 q/a regardless of if the ans are correct?</p>
<p>hey guys i think i got a 80 on math but i dont remember the triangle problem where the answer was 3? could someone please write down the question (or at least as much as they remember?) thanks.</p>
<p>the other 23 i mean^</p>
<ol>
<li>it was x = 2, y =2</li>
</ol>
<p>what’s the question for “. 108 degrees”?</p>
<p>um the one bout triangles n parallel lines ?</p>
<p>Does College Board ever “throw out” PSAT questions?</p>
<p>The resentment/disdain one is making me mad… I put disdain, but I see how resentment would be the ‘better answer choice’.</p>
<p>It was 110 not 108. It was the triangle with the parrallel lines and all that.</p>
<p>or is it 110 degrees? sum students said that</p>
<p>oo yes it is 110</p>
<p>what about the question for “r = 4”?</p>
<p>can someone explain 110 n 108.</p>
<p>r=radius of the 1/2 circle rite?</p>
<p>yea x was 110. 100% confident. At first i put 72 then i looked at the angle and saw that it was greater than 90 so i redid the question. I finished section 4, the second math section, with 8 minutes to spare. I wish they let you go back to critical reading and all.</p>
<p>n the radius was 4 wasnt it?</p>
<p>hey sorry to say it again but please does anyone remember the triangle one with answer 3, i dont remember this at all and its starting to worry me</p>
<p>hold on can someone pleeaaaassssssseeee explain the 110 thing</p>
<p>for the xyz question…i put I and II because x could be -3, y could be -1 and z could be 1 thus resulting in a negative number for yz…idk if thats correct but that was my logic</p>
<p>the perimeter of a triangle equals 8. the middle leg’s max value is?</p>
<p>^^ yeah dats what i got too</p>
<p>does anyone remember the answer for the one where we had to find the probability of getting a sum of 8 with the spinners??? I BLANKED OUT ON THAT!!! i cant believe it</p>
<p>btw IMO i felt the actual SAT math on saturday was a lot easier than the PSAT’s lol</p>
<p>Galib, But then the overall number would be positive; the question said a negative number.</p>
<p>@alihaq
I think the question went something like this:
The three sides of a triangle are integers a, b, c and a<b<c
If the perimeter of the triangle is 8, what is the greatest possible value of b</p>