<p>Just wondering, have anyone taken this practice test? Did anyone think the writing portion was extremely hard? It was the first time for a long time that I got 13 wrong :(</p>
<p>But anyway:</p>
<p>Haven’t taken the 2004 PSAT, but the math question’s an interesting one. </p>
<p>DEF: 3<em>(11+9+7) = 3</em>(7+14+6) = 3<em>(6+11+10) = 3</em>27 = 81</p>
<p>ABC: 3<em>(9+7+14) = 3</em>(9+11+10) = 3<em>(14+6+10) = 3</em> 30 = 90</p>
<p>Answer, then, is 9 units.</p>
<p>Do you see how I got it, or do I need to explain further?</p>
<p>Yeah, did not understand it. Sorry, but why did you multiply?</p>
<p>They’re equilateral triangles. If you have one side, you have all three. You can find any of their three sides. </p>
<p>Since the sides are paralel, the “edge” triangles are also equilateral. So take the top side of DEF:</p>
<p>Part of it is 9, and the other two are 11 and 7, as you can see from the edge triangles. So the sides of DEF are 9+11+7=27, with parameter 3*27=81. </p>
<p>Is that good?</p>
<p>Ohhhhhhhh
i get it :DDD</p>
<p>thank you so much!</p>
<p>Any time.</p>
<p>10char</p>