PSAT Math question

<p>Anyone want to help me with a "tough" PSAT Math question? I would make a thread, but it would probably be ignored because of all the hype from the October 10 SAT.</p>

<p>Anyway, from the Alternate 05 PSAT:
Section 2, Question 19
What is the volume, in cubic inches, of the smallest rectangular box into which a 1-inch cube, a 2-inch cube, and a 3-inch cube can be packed together? (Assume that the cubes are solid.)
(A) 125
(B) 75
(C) 54
(D) 45
(E) 36</p>

<p>Thanks for the help!</p>

<p>Is the answer 54 ACTTester?</p>

<p>^ The answer is actually (D) 45. I ended up choosing (E) 36 myself…</p>

<p>OK, what you do is imagine putting the 3 in cube next to the 2in cube with the 1inch cube on top of the 2in cube. The length would be 5 inches (the 3in + 2in) and the height would be 3 inches. The width would also be 3 inches. So 3 x 3x x5=45</p>