<p>it was only 2 because try a=.5 b=.1</p>
<p>It satisfies the equation, but it goes against III ,where a<b.</p>
<p>x^2 + kx +4 = (x+c)^2 </p>
<p>k had to be 4, becuase it was a square of (x+2)</p>
<p>wasn't the question with b<a when a/b not a<b?</p>
<p>hmmmm.</p>
<p>Not sure, but check back a couple pages in this thread. The consensus was that only II was the right answer.</p>
<p>didnt x^2 + kx +4 = (x+c)^2 ask for c?</p>
<p>no k i thought</p>
<p>for that one circle problem with the tangent lines, did u get h=15.2 or something like that?</p>
<p>It asked for k, the circle problem was 14.x, choice b i think.</p>
<p>Just try out different problems for the a and b one. 1 and 3 do not have to be in effect in order for the problem to work out so that a/b > ab.
Tangent lines problem--h=8+4rad3
for the root problem, the sq rt of x and sq rt of y had to be odd numbers that equaled ten. The answer did not have to be odd (and would not be odd). 49+9 works.
k=2 for the factoring one.</p>
<p>sunshine, so 81 and 1 would work?</p>
<p>Yes, 81 and 1 would work.
9+1=10 and are both odd.</p>
<p>First of all that factoring one asked for c, and the answer was DEFINITELY 2. The answer came out to be 2c=4. So 2 = answer.</p>
<p>81 1 and 49 9 would both work for the other problem also.</p>
<p>yeah(10char)</p>
<p>yeah i remember it asking for k also, and i was like *** why did they put c in there....</p>
<p>wait didnt it ask for k? how could k be 2? Unless i misread "2c" as "k".</p>
<p>Look, about this whole even/odd thing, there is no way that you COULD have found and odd sum for A+B. Either you have 2 odd numbers or 2 evens that sum to 10. Square them both, and you get the same, either two odds or two evens. when you add an odd and an odd, or an even and an even, you get an even number. To back this up more empirically instead of just rambling, here are the possibilities.
1+81=82
4+64=68
9+49=58
16+36=52
25+25=50
they're all even, but i have no idea about this whole odd number thing. There's no way the sum could NOT be even, and I don't recall hearing odd numbers mentioned. If I missed it, perhaps a and b themselves were supposed to be odd, meaning that rad(a) and rad(b) were also odd? Either way, I put 7^(2) + 3^(2) = 49 + 9 = 58, so I think that should work? Does that make sense?</p>
<p>How do you guys think the curve will go?</p>
<p>and K was four. And it definitely asked for K, because I remember looking at C, and freaking out about what it was asking for (maybe it's that they sound kinda similar, idk) and then I checked the question and it was definitely K.</p>
<p>harsh curve on math imo</p>
<p>yeah I think it asked for K also because I was like why is there a C here??</p>
<p>and K was four. And it definitely asked for K, because I remember looking at C, and freaking out about what it was asking for (maybe it's that they sound kinda similar, idk) and then I checked the question and it was definitely K.</p>
<p>I remember re reading it and seeing that it asked for c. And then I got c = 2. I don't know, all I know is that I got 2 and that I'm 98% sure I'm correct.</p>
<p>I also finished the test 1 hour ago.</p>