<p>For #11 - C - lets just say (m+n)=3. So q=4^3</p>
<p>So if 2(m+n)=6. then X=4^6</p>
<p>(4^3)^2 = 4^6</p>
<p>so the answer is q^2</p>
<p>For #14 - B</p>
<p>I. - NO - term 2 is 4 (4^2 = 16)
II. - Yes - 2^0 = 1, 2^2=4, 2^4=16 etc…
III. - NO - Plug in the equation for n = 53,you get 2^104 - which is way more than 6 digits</p>