<p>In my princeton review book, there are two log questions that i have no idea how to do.
<a href="http://i304.photobucket.com/albums/nn181/aconegliano/untitled.jpg%5B/url%5D">http://i304.photobucket.com/albums/nn181/aconegliano/untitled.jpg</a>
i made it into a picture so you can read it better. the answers are
1. y
2. x^2
i dont know how they got those answers.</p>
<p>I think some of the question is cut out, since it says log with a base of 4 but not the number of the exponent.</p>
<p>log(base2)X=log(base4)Y</p>
<p>log(base 4)Y= 2 x log(base 2)Y
log(base2)X= 2 x log(base 2)Y
Y=X^2
and since multiples are exponents, its X^2.</p>
<p>sqrt of 4 is 2 which becomes a multiple.
thus its X^2</p>
<p>don't know if that's right though.
what page is it on the PR book</p>
<p>The first is a property of logs. You just need to know that.</p>
<p>For number two....</p>
<ol>
<li>Rewrite both sides using the change of base formula.</li>
</ol>
<p>log x/log 2 = log ?/log 4</p>
<ol>
<li>Multiply both sides by log 4.</li>
</ol>
<p>log 4/log 2 * log x = log ?</p>
<ol>
<li>Recognize that log 4 = log 2^2, or 2 * log 2. Hence, log 4/log 2 = 2.</li>
</ol>
<p>2 * log x = log ?</p>
<ol>
<li>2 * log x = log x^2</li>
</ol>
<p>log x^2 = log ?</p>
<ol>
<li>Taking the antilog of both sides yields ? = x^2.</li>
</ol>
<p>the questions are 5 and 7 on pg 41. the drill section. i have the 03-04 princeton review book.</p>