<p>how do you solve this equation?</p>
<p>x^(1/2) -5x^(1/4) = 36</p>
<p>it's been bugging me for ages!</p>
<p>bump!</p>
<p>this problem is driving me crazy</p>
<p>Let x^1/4 = x</p>
<p>x^(1/2) -5x^(1/4) = 36
x^2 -5x = 36
x^2-5x-36=0</p>
<p>(x-9)(x+4)
<a href=“x%5E1/4%20-%209”>b</a> (x^1/4 + 4)**</p>
<p>x=9
x=-4</p>
<p>x^1/4=9
x^1/4=-4</p>
<p>raise both sides to the power of 4, multiply exponents by 4
x=9^4=6561
x=(-4)^4=256</p>
<p>check answers, only 6561 works</p>
<p>x=6561</p>
<p>ahh
another question…sorry. </p>
<p>to solve x - sqroot (1-4x) = 0</p>
<p>do u multiply the left hand side with the conjugate in order to get ride of the square-root sign?</p>
<p>x - sqroot(1-4x) = 0
x = sqroot(1-4x)
(x = sqroot(1-4x))^2
x^2 = 1-4x
x^2 + 4x - 1 = 0
quadratic formula</p>
<p>ya i did that initially and got -4.23 and 0.23…but it says it’s not the right answer :/</p>
<p>wats the answer</p>
<p>it doesn’t say cuz its this online site where u enter ur answer and it tells u whether u’re right or wrong…but anywho…when u do plug those numbers back in…it doesn’t = 0…so it doesnt exist?</p>
<p>graph it and u dont get any 0s</p>