<p>a^(x+2) = k</p>
<p>what is this in terms of k, using logs?</p>
<p>(x+2) log a = log k</p>
<p>you can solve for K exactly by taking dk/dt or just leave it as it is</p>
<p>a^(x+2) = k</p>
<p>what is this in terms of k, using logs?</p>
<p>(x+2) log a = log k</p>
<p>you can solve for K exactly by taking dk/dt or just leave it as it is</p>