<p>xy = x+y</p>
<p>If y > 2, what are all the possible values of x that satisfy the equation above?</p>
<p>A) x< 0
B) 0 < x < 1
C) 0 < x <2
D) 1< x < 2
E) x > 2</p>
<p>D?</p>
<p>Just substitute some numbers in for problems like this.</p>
<p>3(X) = X + 3 - Solve for X. X equals 1.5</p>
<p>11(X) = X + 11 - X equals 1.1</p>
<p>15(X) = X + 15 - X equals 1.07</p>
<p>21(X) = X + 21 - X equals 1.05</p>
<p>Do you get it? Just choose 3 or 4 random variables for y, and solve for x. Which answer choice applies? Only D. And that’s your answer.</p>
<p>Now I get it, instead of just choosing y’s i also chose x’s so i guess that doesn’t work. next time just pick one x and solve for that. thanks</p>