<p>for positive integers x and y, 2x+y= 32, and x is less than 8. What is the least possible value of y?</p>
<p>a)16
b)17
c)18
d)20
e)32</p>
<p>the answer is C right?</p>
<p>I saw this online, so i don't have the answer key!</p>
<p>The least possible value of y corresponds to the greatest possible value of x. Since x is a positive integer and less than 8, x = 7 is the greatest possible value of x. Therefore, the least possible value of y satisfies 2 (7) + y = 32. So y = 18 is the least possible value of y.</p>
<p>Answer C.</p>
<p>Since y=32-2x …To lessen the value of why we need to put in the maximum possible value of x…since the condition states x is an integer less than 8 so 7 is the most viable option on substituting y=32-2(7)=18</p>
<p>2x + y = 32
x < 8
The greatest value for x, then, is 7 (you want to maximize x to minimize y).
14 + y = 32
y = 18
The answer is C.</p>