<p>how do i solve: </p>
<p>if y-x=5 and 2y+z=11, what is x+y+z?</p>
<p>thanks</p>
<p>Plug in sample numbers for x, y, and z individually until it fits, then just carry the solution out. (In other words, plug in random numbers for the first equation, then plug in whatever number you chose for y from that into the 2nd equation to get z, then add the variables up.)</p>
<p>Let’s say that I randomly pick 7 for y and 2 for x. z would have to be -3.</p>
<p>7+2-3 = 6</p>
<p>Let’s say that I randomly pick 4 for y and -1 for x. z would have to be 3.
4-1+3 = 6</p>
<p>thank you :)</p>
<p>easier:
(2y+z=11) - (y-x=5) = y+z+x = 6</p>
<p>It’s a really simple System of Equations—just used the subtraction method:</p>
<p>(2y+0x+ z=11)
-( y -x+0z=5)</p>
<hr>
<p>y+x+z=6</p>
<p>i beat you by 4 minutes. YES! :P</p>