<p>I'm learning implicit differentiation right now (by myself) and I don't know how to do this problem</p>
<p>Find dy/dx using implicit differentiation</p>
<p>( ln (xy) ) + y^2 = 1</p>
<p>How do I do this? Can someone explain this to me or solve it?</p>
<p>Thanks.</p>
<p>this is what i got, but for some reason i think it's wrong</p>
<p>ln(xy) + y^2 = 1</p>
<p>...(y+x(dy/dx))/(xy) + 2y(dy/dx) = 0 ---> take derivative of both sides</p>
<p>.....(dy/dx)((y+x)/(xy) + 2y) = 0 ---> factor out (dy/dx) from both terms</p>
<p>.......(dy/dx) = 0/((y+x)/(xy) + 2y) ---> divide</p>
<p>.......... => dy/dx = 0</p>
<p>But I think this is wrong...it's just too convenient.</p>
<p>that's what I got but I didn't post because I thought it was wrong...I still think it's wrong but w/e...</p>