<p>I don't understand the logic of this answer. This is from the 10 new real's.</p>
<p>Question:
There are 75 more women than men enrolled in Linden College. If there are n men enrolled, then, in terms of n, what percentage of those enrolled are men?</p>
<p>What I thought:
(100n)/(n + 75) %</p>
<p>What they say the answer is:
"(100n)/(2n + 75) %</p>
<p>maybe i'm just stupid, but i'm getting what you got.
i arbitrarily picked n=25
men: 25/100 = 25%
(100x25)/(25+75) = 25%</p>
<p>by the way, this is supposed to bea "hard level" question</p>
<p>oh just kidding...</p>
<p>ok so n=25, so there are 100 women
men: 25/125=20%
(100x25)/(125)=20%</p>
<p>so yea-- it's the second one.</p>
<p>rachelvish, just go step by step.</p>
<p>There are "n" men</p>
<p>Since there are 75 more women then men, there are "n+75" women</p>
<p>So, total number of students = # of men +# of women = "n" + "n + 75"= 2n + 75</p>
<p>The percentage of men is equal to total # of men over the total # of students multiplied by 100 = n/(2n+75) *100= 100n/(2n+75)</p>
<p>oh okay this is why:</p>
<p>women = n + 75
men = n</p>
<p>therefore total = 2n + 75</p>
<p>haha man, I should have gotten that</p>
<p>okay haha you posted just as I figured it out... but thats good to remember, to go step by step.</p>