<p>For #5, they're basically asking what's the probability that a > b. There's probably an easier way to do this using combinations or something, but I can't think of it:</p>
<p>So, if a = 6, then there are 5 possible numbers you can land on for b for a > b. If a = 5, there are 4 possibilities; if a = 4, there are 3 possibilities, and so on...</p>
<p>So your total probability that a > b is going to be a fraction (situations which would make the statement true over total possible situations). Since these are the possibilities that are going to make it true, you add them together and put them in the numerator:</p>
<p>5+4+3+2+1 = 15</p>
<p>And your denominator is total possible combinations (not just a > b, but also a < b and a = b), which is 6 x 6.</p>
<p>So the answer is A) 15/36</p>
<p>Sorry for the crappy explanation... hopefully someone can give a better one.</p>
<p>As for #8, you're looking at Q wrong. It's between 1 and 2, not 0 and 1. ;)</p>