<p>^ i used pretty much the same thing
i got
3x^2 – 2x + 7 = 0
3x^2 – 2x = -7
x^2 – 2x/3 = -7/3
then i replaced -7/3+1/9 = -20/9
this was my first option, if things dont work out,or i dont see the algebra, i'd certainly jump to my TI, solve for X, plug in xD</p>
<p>^That's the intended solution. Note that the SAT specifically does not ever require the quadratic formula. Not to say that it can't be used, but it won't be the fastest way. Of course if you have an actual SAT problem that IS faster with the quadratic formula, post away and put me in my place!</p>
<p>Hm, the quadratic equatio for me is the easiest and fastest way to solve that problem. To each his own. Especially because gcf101 didn't get the right answer, nor did Quix originally, and neither just used the very straightforward quadratic equation from the start.</p>
<p>SAT I doesn't use complex numbers in equations, unless its by itself(i,i^2, etc)
All SAT I problems can be solved by hand. o_o</p>
<p>You can solve any problem by hand. </p>
<p>Anyyyyy problem.</p>
<p>
Oops!
I meant
-7/3 + (1/3)^2 = -20/9, so
<a href="x%20-%201/3">b</a>^2 = -20/9** - same as Ren the SAT'er.
It's all Quix's fault! He embedded the wrong answer in my head. ;)</p>