<li>A heat engines high-temperature source has a mass, m, and a specific heat, c. In a cycle of the engine, as it extracts energy from its high-temperature source, the temperature of that source drops by temperature dT (assume 100% efficiency for this heat extraction). The engine then does some work and then exhausts an amount of energy, Q, into a cold reservoir. What is the efficiency of the heat engine?</li>
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<p>my answer to this question was </p>
<p>1-(Q/mc(dT)) since efficiency is given by 1 - (Q1/Q2) and not (1-Q1)/Q2</p>
<p>but the correct answer is given as (1-q)/mc(dt)</p>
<p>That's wrong, the correct answer was something like.. Qh = Qc + Lost
... or something like that. I took the Physics SAT2 in May, and got a 710, but i'm pretty sure I got that one wrong. During discussion after the test on these forums that was discussed. Try doing a search on it, the post was some time a while ago (the day of the SAT2.)</p>
<p>That question is a bit defective (I remember it). The units don't work out correctly. There is no correct answer given in the choices. Don't stress about it.</p>