SAT January 2012 - Math

<p>Michael, it asked for least posible integer of d which was 7</p>

<p>@sat100 gotcha. congrats on what is hopefully a perfect score!!</p>

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<p>a needed to be positive.</p>

<p>^Impossible if A had to also be a positive integer. 0 =/= positive integer</p>

<p>A=1
B=5
C=7
D=8</p>

<p>Nope, a had to be 1 since all the numbers were integers, it wasn’t 0.</p>

<p>I do not understand how it’s not 8…</p>

<p>The number line was 8, since it specified that ALL of the numbers were POSITIVE integers. A was at 1, B was at 5, C at 7, D at 8. </p>

<p>All the other answers already listed are correct 8/3 for the water volume, 4 for the arrangements of ABCDE, 4 for the circle, etc. Absolutely positive about my ans, had time to check each section twice.</p>

<p>Let’s get this straight, did it state that it had to be ABCD IN THAT ORDER and all numbers had to be positive</p>

<p>Nooo damn stupid mistake</p>

<p>The answer was 8</p>

<p>@chewydog, wasn’t there a picture?</p>

<p>They’re points on a line, you either flip the line but the order stays the same, either way, it gives the same answer</p>

<p>Its 7 if you count 0 as an integer. But 0 is not an integer.</p>

<p>What was the one before that?</p>

<p>Well hopefully its a leniet curve…</p>

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0 is an integer… It’s just not positive.</p>

<p>How about the distance between the intercepts? I know what I got but I don’t want to be the first one to say it… (y =-4/3x + 8)</p>

<p>Lol it was 8… 0 is not a positive integer.</p>

<p>@GoodJobBro
Are you talking about the parabola one? I got 3/2 for that… used calculus lol. </p>

<p>Math was pretty easy IMO.</p>

<p>@runallday: Oh yeah…there was a picture. I had forgotten in my post-test hype. Thank you for the reminder. Thus, D had to have been 8.</p>

<p>@Bro: 10. 3-4-5 triangle.</p>

<p>@zzzzzz: I ALSO USED CALC!!! y’ right? :slight_smile: (But somehow I got 3/2…y’=2x-3 x=3/2 when y’=0)</p>

<p>Was it 10?</p>