<p>1) The numbers zero to ten are evenly spaced on a number line, with Q as 1, and R as 10. If this line is divided into three equal parts by points M and N, which of the following is a possible coordinate for point N?</p>
<p>a) 3 b) 5 c) 6 d) 7 e) 9</p>
<p>2) Points FGH all lie on the same line such that G lies between F and G. Which of the following must be true?</p>
<p>I. H is between G and J
II. F is between H and G
III. G is between H and J</p>
<p>a) None b) I only c) II only d) III only e) II and III only</p>
<p>3) Robert drove from Lefton to Righterly. Two hours into the trip, he pulled into Serose, which is one-fifth of the distance to Righterly. After lunch, Robert drove 225 miles to Brighton. If the distance from Brighton to Righterly is 95 miles, what is the total distance from Lefton to Righterly?</p>
<p>a) 320 b) 380 c) 400 d) 475 e) 900</p>
<p>Thanks :)</p>
<p>1) We can see that M and N have to be 4,7 or 7,4 because 4-1=3, 7-4=3, and 10-7=3 so they are equally spaced.</p>
<p>7 is the only option, so C.</p>
<p>1) The numbers zero to ten are evenly spaced on a number line, with Q as 1, and R as 10. If this line is divided into three equal parts by points M and N, which of the following is a possible coordinate for point N?</p>
<p>a) 3 b) 5 c) 6 d) 7 e) 9</p>
<p>The total distance between Q and R would be 10, and if this distance is divided into three equal parts, one part would be about 3.3 (10/3). Since N is farther away from Q than M, N is 3.3+3.3=6.67, which is close to 7. The answer is D.</p>
<p>Sorry I don’t get ur second question. Alphabets are missing, I guess.</p>
<p>3) Robert drove from Lefton to Righterly. Two hours into the trip, he pulled into Serose, which is one-fifth of the distance to Righterly. After lunch, Robert drove 225 miles to Brighton. If the distance from Brighton to Righterly is 95 miles, what is the total distance from Lefton to Righterly?</p>
<p>a) 320 b) 380 c) 400 d) 475 e) 900</p>
<p>So, the distance from Lefton to Serose is x/5, if x is the total distance from Lefton to Righterly, which means that the leftover distance from Serose to Righterly past Brighton is 4x/5 of the total distance. The distance from Serose to Righterly past Brighton is 225+95=320. 4x/5=320, x=400. The answer is C.</p>
<p>Hope this helped you :)</p>
<p>The distance from Serose to Righterly is 95+225=320 which is 4/5 the disance. Therefore the total is 320*5/4=400 which is B.</p>
<p>Sorry again, 400 is C, I’m on my iPod so I have to memorize the problem and the answers while I type out my response :P.</p>
<p>thanks 
and #2 came just like that, as i posted
so that was kaplan’s fault for clarity issues</p>